1. Chapter 5 Class 10 Arithmetic Progressions
  2. Serial order wise
  3. Ex 5.3

Ex 5.3, 9 - Chapter 5 Class 10 Arithmetic Progressions

Last updated at June 29, 2018 by

Ex 5.3, 9 - If sum of first 7 terms of an AP is 49 - Determining AP and finding sum

  1. Chapter 5 Class 10 Arithmetic Progressions
  2. Serial order wise

    3. Ex 5.3

    Examples →

Transcript

Ex 5.3 ,9 If the sum of first 7 terms of an AP is 49 and that of 17 terms is 289, find the sum of first n terms. We know that Sn = ๐‘›/2 (2๐‘Ž+(๐‘›โˆ’1)๐‘‘) From (1) and (2) 7 โ€“ 3d = 17 โ€“ 8d 8d โ€“ 3d = 17 โ€“ 7 5d = 10 d = 10/5 d = 2 Putting value of d in (1) a = 7 โ€“ 3d a = 7 โ€“ 3 ร—2 a = 7 โ€“ 6 a = 1 Hence, a = 1 & d = 2 We need to find sum of first n terms We can use formula Sn = ๐‘›/2 (2a + (n โ€“ 1) d) = ๐‘›/2 (2 ร—1+(๐‘›โˆ’1)2) = ๐‘›/2(2+2๐‘›โˆ’2) = ๐‘›/2 (0 + 2n) = ๐‘›/2ร—2๐‘› = n2

Chapter 5 Class 10 Arithmetic Progressions
Serial order wise

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.