

Ex 5.3
Ex 5.3, 1 (ii) You are here
Ex 5.3, 1 (iii) Important
Ex 5.3, 1 (iv)
Ex 5.3, 2 (i)
Ex 5.3, 2 (ii)
Ex 5.3, 2 (iii) Important
Ex 5.3, 3 (i)
Ex 5.3, 3 (ii)
Ex 5.3, 3 (iii)
Ex 5.3, 3 (iv) Important
Ex 5.3, 3 (v)
Ex 5.3, 3 (vi) Important
Ex 5.3, 3 (vii)
Ex 5.3, 3 (viii) Important
Ex 5.3, 3 (ix)
Ex 5.3, 3 (x)
Ex 5.3, 4
Ex 5.3, 5
Ex 5.3, 6 Important
Ex 5.3, 7
Ex 5.3, 8
Ex 5.3, 9
Ex 5.3, 10 (i)
Ex 5.3, 10 (ii) Important
Ex 5.3, 11 Important
Ex 5.3, 12
Ex 5.3, 13
Ex 5.3, 14 Important
Ex 5.3, 15 Deleted for CBSE Board 2022 Exams
Ex 5.3, 16 Important Deleted for CBSE Board 2022 Exams
Ex 5.3, 17 Deleted for CBSE Board 2022 Exams
Ex 5.3, 18 Important Deleted for CBSE Board 2022 Exams
Ex 5.3, 19 Important Deleted for CBSE Board 2022 Exams
Ex 5.3, 20 Important Deleted for CBSE Board 2022 Exams
Last updated at Aug. 3, 2021 by Teachoo
Ex 5.3, 1 Find the sum of the following APs. (ii) −37, −33, −29 ,…, to 12 terms –37, –33, –29 ,…, to 12 terms We know that Sum = 𝑛/2 (2a + (n – 1)d) Here n = 12, a = –37 & d = – 33 – (–37) = – 33 + 37 = 4 Putting values in formula Sum = 𝒏/𝟐 (2a + (n – 1) d) = 12/2 (2 × (–37) + (12 – 1) × 4) = 6 (–74 + 11 × 4) = 6 (–74 + 44) = 6 (–30) = –180