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Ex 5.3, 11 - If sum of first n terms of AP is 4n - n2 - Ex 5.3

  1. Chapter 5 Class 10 Arithmetic Progressions
  2. Serial order wise
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Ex 5.3 ,11 If the sum of the first n terms of an AP is 4n − n2, what is the first term (that is S1)? What is the sum of first two terms? What is the second term? Similarly find the 3rd, the10th and the nth terms. Given Sn = 4n – n2 Taking n = 1 S1 = 4 ×1−12 = 4 – 1 = 3 So, Sum of first term of AP is 3 But sum of first term will be the first term So, First term = a = 3 Taking n = 2 in Sn S2 = 4×2−2^2 S2 = 8 – 4 S2 = 4 ∴ Sum of first 2 terms is 4 Finding 2nd term Sum of first 2 terms is 4 First term + Second term = 4 3 + a2 = 4 a2 = 4 – 3 a2 = 1 Hence in AP , First term = a = 3 Common difference = d = Second term – First term = 1 – 3 = –2 We need to find 3rd, 10th and nth term We know that an = a + (n – 1) d Third term a3 = a + (3 – 1) d = a + 2d = 3 + 2 ×(−2) = 3 – 4 = – 1 10th term a10 = a + (10 – 1) d = a + 9d = 3 + 9 × – 2 = 3 – 18 = – 15 nth term an = a + (n – 1)d = 3 + (n – 1) × ( – 2) = 3 + n (–2) – 1 ×( – 2) = 3 –2n + 2 = 5 – 2n

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