Last updated at Dec. 16, 2024 by Teachoo
Question 1 Using mathematical induction prove that ๐/๐๐ฅ(๐ฅ^๐) = ใ๐๐ฅใ^(๐โ1) for all positive integers ๐. Let ๐(๐) : ๐/๐๐ฅ (๐ฅ^๐) = ใ๐๐ฅใ^(๐โ1) For ๐ = ๐ Solving LHS (๐(๐ฅ^1)" " )/๐๐ฅ = ๐๐ฅ/๐๐ฅ = 1 = RHS Thus, ๐ท(๐) is true for ๐ = 1 Let us assume that ๐ท(๐) is true for ๐โ๐ต ๐ท(๐) : (๐ (๐ฅ^๐))/๐๐ฅ = ใ๐ ๐ฅใ^(๐โ1) Now We have to prove that P(๐+๐) is true ๐(๐+1) : (๐(๐ฅ^(๐ + 1))" " )/๐๐ฅ = ใ(๐+1) ๐ฅใ^(๐ + 1 โ 1) (๐(๐ฅ^(๐ + 1)))/๐๐ฅ = ใ(๐+1) ๐ฅใ^๐ Taking L.H.S (๐(๐ฅ^(๐ + 1)))/๐๐ฅ = (๐(๐ฅ^(๐ ). ๐ฅ))/๐๐ฅ Using product rule As (๐ข๐ฃ)โ = ๐ขโ๐ฃ + ๐ฃโ๐ข where u = xk & v = x = (๐(๐ฅ^๐)" " )/๐๐ฅ . ๐ฅ + ๐(๐ฅ )/๐๐ฅ . ๐ฅ^(๐ ) = (๐ (๐^๐)" " )/๐ ๐ . ๐ฅ + 1 . ๐ฅ^(๐ ) = (ใ๐. ๐ใ^(๐โ๐) ) . ๐ฅ+๐ฅ^๐ = ใ๐. ๐ฅใ^(๐โ1 + 1) .+๐ฅ^๐ = ใ๐. ๐ฅใ^๐+๐ฅ^๐ = ๐ฅ^๐ (๐+1) = R.H.S Hence proved (From (1): (๐(๐ฅ^๐ ") " )/๐๐ฅ = ใ๐ ๐ฅใ^(๐โ1) ) Thus , ๐ท(๐+๐) is true when ๐ท(๐) is true Therefore, By Principle of Mathematical Induction ๐(๐) : ๐/๐๐ฅ (๐ฅ^๐) = ใ๐๐ฅใ^(๐โ1) is true for all ๐โ๐ต
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo