Last updated at Dec. 16, 2024 by Teachoo
Misc 1 Differentiate w.r.t. x the function, (3๐ฅ2 โ 9๐ฅ + 5)^9Let ๐ฆ=(3๐ฅ2 โ 9๐ฅ + 5)^9 Differentiating ๐ค.๐.๐ก.๐ฅ. ๐๐ฆ/๐๐ฅ = (๐(3๐ฅ2 โ 9๐ฅ + 5)^9)/๐๐ฅ = 9(3๐ฅ2 โ 9๐ฅ + 5)^(9 โ1) . ๐(3๐ฅ2 โ 9๐ฅ + 5)/๐๐ฅ = 9(3๐ฅ2 โ 9๐ฅ + 5)^8 . (๐(3๐ฅ2)/๐๐ฅ โ ๐(9๐ฅ)/๐๐ฅ โ ๐(5)/๐๐ฅ) = 9(3๐ฅ2 โ 9๐ฅ + 5)^8 . (6๐ฅโ9+0) = 9(3๐ฅ2 โ 9๐ฅ + 5)^8 . (6๐ฅโ9) = 9(3๐ฅ2 โ 9๐ฅ + 5)^8 . 3(2๐ฅโ3) = ๐๐(๐๐๐ โ ๐๐ + ๐)^๐ (๐๐โ๐)
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo