# Ex 2.2, 2 - Chapter 2 Class 12 Inverse Trigonometric Functions (Term 1)

Last updated at May 12, 2021 by Teachoo

Ex 2.2

Ex 2.2,1
Deleted for CBSE Board 2022 Exams

Ex 2.2, 2 Important Deleted for CBSE Board 2022 Exams You are here

Ex 2.2, 3 Deleted for CBSE Board 2022 Exams

Ex 2.2, 4 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 5 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 6 Deleted for CBSE Board 2022 Exams

Ex 2.2, 7 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 8 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 9 Deleted for CBSE Board 2022 Exams

Ex 2.2, 10 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 11 Deleted for CBSE Board 2022 Exams

Ex 2.2, 12 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 13 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 14 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 15 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 16 Deleted for CBSE Board 2022 Exams

Ex 2.2, 17 Deleted for CBSE Board 2022 Exams

Ex 2.2, 18 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 19 (MCQ) Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 20 (MCQ) Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 21 (MCQ) Deleted for CBSE Board 2022 Exams

Chapter 2 Class 12 Inverse Trigonometric Functions (Term 1)

Serial order wise

Last updated at May 12, 2021 by Teachoo

Ex 2.2, 2 3cosβ1 π₯ = cosβ1 (4π₯^3β 3π₯ ), π₯β [1/2,1] Solving R.H.S cos^(β1) (4π₯^3β 3π₯ ) Putting x = cos π = cos^(β1) (4 γ"cos" γ^ππ β 3cos π) = cos^(β1) (cos 3π) = 3π = 3 cos^(β1) x (cos 3x = 4 cos^3x β 3 cos x) Now, x = cos π β΄ cos^(β1) (x) = π = L.H.S Hence, proved.