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Last updated at Feb. 13, 2020 by Teachoo

Transcript

Ex 2.2, 2 3cosโ1 ๐ฅ = cosโ1 (4๐ฅ^3โ 3๐ฅ ), ๐ฅโ [1/2,1] Solving R.H.S cos^(โ1) (4๐ฅ^3โ 3๐ฅ ) Putting x = cos ๐ = cos^(โ1) (4 ใ"(cos ๐)" ใ^3โ 3cos ๐) = cos^(โ1) (4 ใ"cos" ใ^๐๐ โ 3cos ๐) = cos^(โ1) (cos 3๐ ) = 3๐ (cos 3x = 4 cos^3x โ 3 cos x) (cos^(โ1) (cos x) = x ) Now, x = cos ๐ โด cos^(โ1) (x) = ๐ = 3 cos^(โ1) x = L.H.S Hence, proved.

Ex 2.2

Ex 2.2,1
Not in Syllabus - CBSE Exams 2021

Ex 2.2, 2 Important Not in Syllabus - CBSE Exams 2021 You are here

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Chapter 2 Class 12 Inverse Trigonometric Functions

Serial order wise

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.