Misc 1 - Chapter 2 Class 12 Inverse Trigonometric Functions

Last updated at August 5, 2026 by

Misc 1 - Find cos-1 (cos 13pi/6) - Chapter 2 Class 12 NCERT - Miscellaneous

part 2 - Misc 1 - Miscellaneous - Serial order wise - Chapter 2 Class 12 Inverse Trigonometric Functions

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Misc 1 Find the value of cos-1 (cos⁡〖13π/6〗 ) Let y = cos-1 (cos⁡〖13π/6〗 ) cos y = cos 13π/6 cos y = cos (390°) But, Range of cos−1 is [0, π] i.e. [0°, 180°] Hence, y = 390° not possible Now, cos y = cos (390°) cos y = cos (360° + 30°) cos y = cos (30°) cos y = cos (𝜋/6) ∴ y = 𝝅/𝟔 Which is in the range of cos-1 i.e. [0, π] Hence , cos −1 (cos 13π/6 " " ) = 𝝅/𝟔

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