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Last updated at Feb. 13, 2020 by Teachoo
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Example 1 Find the principal value of sin–1 (1/√2). Let y = sin–1 (1/√2) sin y = 1/√2 sin y = sin (𝜋/4) Range of principal value of sin −1 is between (−𝜋)/2 and ( 𝜋)/2 Hence, principal value is 𝝅/𝟒 Rough We know that sin 45° = 1/√2 θ = 45° = 45 × 𝜋/180 = 𝜋/4 Since 1/√2 is positive Principal value is θ i.e. 𝜋/4
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Example 6 Important Not in Syllabus - CBSE Exams 2021
Example 7 Not in Syllabus - CBSE Exams 2021
Example 8 Not in Syllabus - CBSE Exams 2021
Example 9 Important
Example 10 Important Not in Syllabus - CBSE Exams 2021
Example 11 Important Not in Syllabus - CBSE Exams 2021
Example 12 Important Not in Syllabus - CBSE Exams 2021
Example 13 Important Not in Syllabus - CBSE Exams 2021
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