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Example 6 - Chapter 2 Class 12 Inverse NCERT - cot-1 - Examples

Example 6 - Chapter 2 Class 12 Inverse Trigonometric Functions - Part 2



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Example 6 Write cotβˆ’1 (1/√(π‘₯^2 βˆ’ 1)), |π‘₯| > 1 in the simplest form. cot-1 (1/√(π‘₯^2 βˆ’ 1)) Putting x = sec ΞΈ = cotβˆ’1 (1/√(γ€–π¬πžπœγ€—^πŸβ‘π›‰ βˆ’ 1)) = cotβˆ’1 (1/√(γ€–(𝟏 + γ€–π­πšπ§γ€—^πŸγ€—β‘πœ½ ) βˆ’ 1)) = cotβˆ’1 (1/√(tan^2⁑θ )) We write 1/√(π‘₯^2 βˆ’ 1) in form of cot Whenever there is √(π‘₯^2βˆ’1) , we put x = sec ΞΈ = cotβˆ’1 (1/tan⁑θ ) = cotβˆ’1 (cot ΞΈ) = ΞΈ We assumed x = sec ΞΈ sec ΞΈ = x ΞΈ = secβˆ’1 x Hence, our equation becomes cotβˆ’1 (1/√(π‘₯^2βˆ’1)) = ΞΈ cotβˆ’1 (1/√(π‘₯^2βˆ’1)) = secβˆ’1 x

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.