Example 6 - Chapter 2 Class 12 Inverse NCERT - cot-1 - Examples

Example 6 - Chapter 2 Class 12 Inverse Trigonometric Functions - Part 2


  1. Chapter 2 Class 12 Inverse Trigonometric Functions (Term 1)
  2. Serial order wise

Transcript

Example 6 Write cotβˆ’1 (1/√(π‘₯^2 βˆ’ 1)), |π‘₯| > 1 in the simplest form. cot-1 (1/√(π‘₯^2 βˆ’ 1)) Putting x = sec ΞΈ = cotβˆ’1 (1/√(γ€–π¬πžπœγ€—^πŸβ‘π›‰ βˆ’ 1)) = cotβˆ’1 (1/√(γ€–(𝟏 + γ€–π­πšπ§γ€—^πŸγ€—β‘πœ½ ) βˆ’ 1)) = cotβˆ’1 (1/√(tan^2⁑θ )) We write 1/√(π‘₯^2 βˆ’ 1) in form of cot Whenever there is √(π‘₯^2βˆ’1) , we put x = sec ΞΈ = cotβˆ’1 (1/tan⁑θ ) = cotβˆ’1 (cot ΞΈ) = ΞΈ We assumed x = sec ΞΈ sec ΞΈ = x ΞΈ = secβˆ’1 x Hence, our equation becomes cotβˆ’1 (1/√(π‘₯^2βˆ’1)) = ΞΈ cotβˆ’1 (1/√(π‘₯^2βˆ’1)) = secβˆ’1 x

About the Author

Davneet Singh's photo - Teacher, Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.