Last updated at Dec. 24, 2021 by

Transcript

Ex 2.2, 1 3sin-1 π₯ = sin-1 (3π₯ β 4π₯^3), π₯β [β1/2,1/2] Solving R.H.S sin^(β1) (3π₯ β 4π₯^3) Putting x = sin π = sin^(β1) (3 sin π β 4 γ"sin" γ^3π) = sin^(β1) (sin 3π ) = 3π = 3 γπππγ^(βπ) x Now, x = sin π sinβ1 x = π (sin 3x = 3 sin x β 4 γπ ππγ^3x) (γπ ππγ^(β1) (sin x) = x ) = L.H.S Hence, proved.

Ex 2.2

Ex 2.2,1
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Ex 2.2, 2 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 3 Deleted for CBSE Board 2022 Exams

Ex 2.2, 4 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 5 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 6 Deleted for CBSE Board 2022 Exams

Ex 2.2, 7 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 8 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 9 Deleted for CBSE Board 2022 Exams

Ex 2.2, 10 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 11 Deleted for CBSE Board 2022 Exams

Ex 2.2, 12 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 13 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 14 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 15 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 16 Deleted for CBSE Board 2022 Exams

Ex 2.2, 17 Deleted for CBSE Board 2022 Exams

Ex 2.2, 18 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 19 (MCQ) Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 20 (MCQ) Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 21 (MCQ) Deleted for CBSE Board 2022 Exams

Chapter 2 Class 12 Inverse Trigonometric Functions (Term 1)

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.