Ex 2.2
Last updated at December 16, 2024 by Teachoo
Transcript
Ex 2.2, 1 3sin-1 š„ = sin-1 (3š„ ā 4š„^3), š„ā [ā1/2,1/2] Solving R.H.S sin^(ā1) (3š„ ā 4š„^3) Putting x = sin š = sin^(ā1) (3 sin š ā 4 ć"sin" ć^3š) = sin^(ā1) (sin 3š ) = 3š = 3 ćšššć^(āš) x = L.H.S Hence, proved.