
Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Ex 2.2
Ex 2.2, 2 Important
Ex 2.2, 3 Important
Ex 2.2, 4 Important
Ex 2.2, 5 Important
Ex 2.2, 6
Ex 2.2, 7 Important
Ex 2.2, 8
Ex 2.2, 9 Important
Ex 2.2, 10
Ex 2.2, 11
Ex 2.2, 12 Important
Ex 2.2, 13 (MCQ) Important
Ex 2.2, 14 (MCQ) Important
Ex 2.2, 15 (MCQ)
Question 1 Deleted for CBSE Board 2024 Exams
Question 2 Important Deleted for CBSE Board 2024 Exams
Question 3 Deleted for CBSE Board 2024 Exams
Question 4 Important Deleted for CBSE Board 2024 Exams
Question 5 Important Deleted for CBSE Board 2024 Exams
Question 6 Important Deleted for CBSE Board 2024 Exams
Last updated at May 29, 2023 by Teachoo
Ex 2.2, 1 3sin-1 π₯ = sin-1 (3π₯ β 4π₯^3), π₯β [β1/2,1/2] Solving R.H.S sin^(β1) (3π₯ β 4π₯^3) Putting x = sin π = sin^(β1) (3 sin π β 4 γ"sin" γ^3π) = sin^(β1) (sin 3π ) = 3π = 3 γπππγ^(βπ) x Now, x = sin π sinβ1 x = π (sin 3x = 3 sin x β 4 γπ ππγ^3x) (γπ ππγ^(β1) (sin x) = x ) = L.H.S Hence, proved.