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Ex 2.2
Ex 2.2, 2 Important
Ex 2.2, 3
Ex 2.2, 4 Important
Ex 2.2, 5 Important
Ex 2.2, 6
Ex 2.2, 7 Important
Ex 2.2, 8 Important
Ex 2.2, 9
Ex 2.2, 10 Important
Ex 2.2, 11
Ex 2.2, 12 Important
Ex 2.2, 13 Important
Ex 2.2, 14 Important
Ex 2.2, 15 Important
Ex 2.2, 16
Ex 2.2, 17
Ex 2.2, 18 Important
Ex 2.2, 19 (MCQ) Important
Ex 2.2, 20 (MCQ) Important
Ex 2.2, 21 (MCQ)
Last updated at Dec. 24, 2021 by Teachoo
Ex 2.2, 1 3sin-1 π₯ = sin-1 (3π₯ β 4π₯^3), π₯β [β1/2,1/2] Solving R.H.S sin^(β1) (3π₯ β 4π₯^3) Putting x = sin π = sin^(β1) (3 sin π β 4 γ"sin" γ^3π) = sin^(β1) (sin 3π ) = 3π = 3 γπππγ^(βπ) x Now, x = sin π sinβ1 x = π (sin 3x = 3 sin x β 4 γπ ππγ^3x) (γπ ππγ^(β1) (sin x) = x ) = L.H.S Hence, proved.