Ex 2.2, 6 - Chapter 2 Class 12 Inverse Trigonometric Functions
Last updated at May 29, 2018 by Teachoo
Transcript
Ex 2.2, 6 Write the function in the simplest form: tan-1 1/ ( ^2 1), |x| > 1 tan-1 (1/ ( ^2 1)) Putting x = sec = tan-1 (1/ (sec^2 1)) = tan-1 (1/ ( (1 + tan^2 ) 1)) = tan-1 (1/ ( 1 1 + tan^2 )) = tan-1 (1/ (tan^2 )) = tan-1 (1/tan ) = tan-1 (cot ) = tan-1 tan (90 ) = 90 = /2 We assumed x = sec sec = x = sec-1 x Hence tan-1 (1/ ( ^2 1)) = /2 = /2 sec-1 x
Chapter 2 Class 12 Inverse Trigonometric Functions
Serial order wise
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.
why we didn't take x = cosecø instead of secø?if we take x = cosec then we get tan~1(1/cotø).