Ex 2.2, 6 - Chapter 2 Class 12 Inverse Trigonometric Functions (Term 1)

Last updated at May 12, 2021 by Teachoo

Ex 2.2, 6 - Simplify: tan-1 1/root (x2-1) - Class 12 Inverse

Ex 2.2, 6 - Chapter 2 Class 12 Inverse Trigonometric Functions - Part 2

Transcript

Ex 2.2, 6 Write the function in the simplest form: tan−1 1/√(𝑥^2−1), |x| > 1 tan−1 (1/√(𝑥^2 − 1)) Putting x = sec θ = tan−1 (1/√(〖𝒔𝒆𝒄〗^𝟐⁡𝜽 − 1)) = tan−1 (1/√(〖(𝟏 + 〖𝒕𝒂𝒏〗^𝟐〗⁡𝜽 ) − 1)) = tan−1 (1/√(tan^2⁡θ )) = tan−1 (1/tan⁡θ ) We write 1/√(𝑥^2 − 1) in form of tan Whenever there is √(𝑥^2−1) , we put x = sec θ = tan−1 (cot θ) = tan−1 tan (90 – θ) = 90 – θ = 𝝅/𝟐 – θ We assumed x = sec θ sec θ = x θ = sec-1 x Hence, our equation becomes tan-1 (1/√(𝑥^2−1)) = 𝜋/2 – θ = 𝝅/𝟐 – sec−1 x (cot θ = tan (90 – θ) )

Ex 2.2

Ex 2.2, 6 Important Deleted for CBSE Board 2022 Exams You are here

Examples →

Chapter 2 Class 12 Inverse Trigonometric Functions (Term 1)

Serial order wise

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.