
Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Ex 2.2
Ex 2.2, 2 Important
Ex 2.2, 3 Important
Ex 2.2, 4 Important
Ex 2.2, 5 Important
Ex 2.2, 6
Ex 2.2, 7 Important
Ex 2.2, 8
Ex 2.2, 9 Important
Ex 2.2, 10
Ex 2.2, 11
Ex 2.2, 12 Important
Ex 2.2, 13 (MCQ) Important
Ex 2.2, 14 (MCQ) Important
Ex 2.2, 15 (MCQ)
Question 1 Deleted for CBSE Board 2024 Exams You are here
Question 2 Important Deleted for CBSE Board 2024 Exams
Question 3 Deleted for CBSE Board 2024 Exams
Question 4 Important Deleted for CBSE Board 2024 Exams
Question 5 Important Deleted for CBSE Board 2024 Exams
Question 6 Important Deleted for CBSE Board 2024 Exams
Last updated at May 29, 2023 by Teachoo
Question 1 Prove tan−1 2/11 + tan−1 7/24 = tan−1 1/2 Solving L.H.S. tan-1 2/11 + tan−1 7/24 = "tan−1" ((2/11 + 7/24)/(1− 2/11 × 7/24)) We know that tan-1 x + tan−1 y = tan−1 ((𝒙+𝒚 )/(𝟏 −𝒙𝒚)) Replace x by 2/11 and y by 7/24= tan-1 (((24 × 2 + 7 × 11)/(24 × 11))/((11 × 12 − 7)/(11 × 12))) = tan-1 (((48 + 77)/(24 × 11))/((132 − 7)/(11 × 12))) = tan-1 ((125/(24 × 11))/(125/(11 × 12))) = tan-1 (125/(24 × 11) × (11 × 12)/125) = tan−1 (1/2) = R.H.S. Hence. R.H.S. = L.H.S. Hence Proved