# Ex 2.2, 8 - Chapter 2 Class 12 Inverse Trigonometric Functions (Term 1)

Last updated at May 12, 2021 by Teachoo

Ex 2.2

Ex 2.2,1
Deleted for CBSE Board 2022 Exams

Ex 2.2, 2 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 3 Deleted for CBSE Board 2022 Exams

Ex 2.2, 4 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 5 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 6 Deleted for CBSE Board 2022 Exams

Ex 2.2, 7 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 8 Important Deleted for CBSE Board 2022 Exams You are here

Ex 2.2, 9 Deleted for CBSE Board 2022 Exams

Ex 2.2, 10 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 11 Deleted for CBSE Board 2022 Exams

Ex 2.2, 12 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 13 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 14 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 15 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 16 Deleted for CBSE Board 2022 Exams

Ex 2.2, 17 Deleted for CBSE Board 2022 Exams

Ex 2.2, 18 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 19 (MCQ) Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 20 (MCQ) Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 21 (MCQ) Deleted for CBSE Board 2022 Exams

Chapter 2 Class 12 Inverse Trigonometric Functions (Term 1)

Serial order wise

Last updated at May 12, 2021 by Teachoo

Hello! Teachoo has made these pages with hours (even days!) of effort and love. Your Board exams are coming, if Teachoo has been of any help in the whole year of studying... please consider making a donation to support us.

Hello! Teachoo has made these pages with hours (even days!) of effort and love. Your Board exams are coming, if Teachoo has been of any help in the whole year of studying... please consider making a donation to support us.

Ex 2.2, 8 Write the function in the simplest form: tan−1 (cos〖x − sinx 〗/cos〖x + sinx 〗 ), 0 < x < π tan−1 (cos〖x − sinx 〗/cos〖x + sinx 〗 ) Dividing by cos x inside = tan−1 (((cos𝑥 − sinx)/cos𝑥 )/((cos𝑥 + sinx)/cos𝑥 )) = tan−1 (((cos x)/cos〖x 〗 − (sin x)/cos〖x 〗 )/((cos x)/cos〖x 〗 + (sin x)/cos〖x 〗 )) = tan−1 ((1 − tanx)/(1 +〖 tan〗x )) We write 𝐜𝐨𝐬〖𝐱 − 𝐬𝐢𝐧𝐱 〗/𝐜𝐨𝐬〖𝐱 + 𝐬𝐢𝐧𝐱 〗 in form of tan We know that tan (x – y) = 𝑡𝑎𝑛〖𝑥 −〖 𝑡𝑎𝑛〗〖𝑦 〗 〗/(1+ 𝑡𝑎𝑛〖𝑥 𝑡𝑎𝑛𝑦 〗 ) So, we divide whole equation by cos = tan−1 ((1 − tanx)/(1 +〖 1 . tan〗x )) = tan−1 ((𝒕𝒂𝒏〖 𝝅/𝟒〗 − tan𝑥)/(1 + 〖𝐭𝐚𝐧 〗〖𝝅/𝟒 .〖 tan〗𝑥 〗 )) = tan−1 ("tan " (𝜋/4−𝑥)) = 𝝅/𝟒 − x Using tan (x – y ) = 𝒕𝒂𝒏〖𝒙 −〖 𝒕𝒂𝒏〗〖𝒚 〗 〗/(𝟏+ 𝒕𝒂𝒏〖𝒙 𝒕𝒂𝒏𝒚 〗 ) Replace x by 𝜋/4 and y by x (As tan 𝜋/4 = 1 )