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Ex 2.2

Ex 2.2,1

Ex 2.2, 2 Important

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Ex 2.2, 5 Important

Ex 2.2, 6 You are here

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Ex 2.2, 12 Important

Ex 2.2, 13 (MCQ) Important

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Question 1 Deleted for CBSE Board 2024 Exams

Question 2 Important Deleted for CBSE Board 2024 Exams

Question 3 Deleted for CBSE Board 2024 Exams

Question 4 Important Deleted for CBSE Board 2024 Exams

Question 5 Important Deleted for CBSE Board 2024 Exams

Question 6 Important Deleted for CBSE Board 2024 Exams

Chapter 2 Class 12 Inverse Trigonometric Functions

Serial order wise

Last updated at May 29, 2023 by Teachoo

Ex 2.2, 6 Write the function in the simplest form: tan-1 𝑥/√(𝑎^2 − 𝑥^2 ) , |x| < a tan-1 𝑥/√(𝑎^2 − 𝑥^2 ) Let x = a sin 𝜽 = tan-1 ((a sinθ)/√(a^2−(a sinθ)^2 )) = tan-1 ((a sinθ)/√(a^2 − a^2 sin2θ)) = tan-1 ((a sinθ)/√(a^2 (1 − sin^2 θ))) = tan-1 ((a sinθ)/(a√(1 − sin^2 θ))) = tan-1 (sinθ/√(cos^2 θ)) We write 𝒙/√(𝒂^𝟐 − 𝒙^𝟐 ) in form of tan Whenever there is √(1 − 𝑥^2 ) we put x = cos θ or sin θ In √(𝒂^𝟐 − 𝒙^𝟐 ) , we put x = a cos θ or a sin θ = tan-1 ((a sinθ)/(a√(1 − sin^2 θ))) = tan-1 (sinθ/√(cos^2 θ)) = tan-1 (sinθ/〖 cos〗θ ) = tan-1 (tan θ) = 𝛉 We assumed that x = a sin θ 𝑥/𝑎 = sin θ sin-1 𝒙/𝒂 = θ Hence, tan-1 𝑥/√(𝑎^2 − 𝑥^2 ) = θ = sin-1 𝒙/𝒂