Last updated at May 12, 2021 by Teachoo

Transcript

Ex 2.2, 9 Write the function in the simplest form: tan-1 𝑥/√(𝑎^2 − 𝑥^2 ) , |x| < a tan-1 𝑥/√(𝑎^2 − 𝑥^2 ) Let x = a sin 𝜽 = tan-1 ((a sinθ)/√(a^2−(a sinθ)^2 )) = tan-1 ((a sinθ)/√(a^2 − a^2 sin2θ)) = tan-1 ((a sinθ)/√(a^2 (1 − sin^2 θ))) = tan-1 ((a sinθ)/(a√(1 − sin^2 θ))) = tan-1 (sinθ/√(cos^2 θ)) We write 𝒙/√(𝒂^𝟐 − 𝒙^𝟐 ) in form of tan Whenever there is √(1 − 𝑥^2 ) we put x = cos θ or sin θ In √(𝒂^𝟐 − 𝒙^𝟐 ) , we put x = a cos θ or a sin θ = tan-1 ((a sinθ)/(a√(1 − sin^2 θ))) = tan-1 (sinθ/√(cos^2 θ)) = tan-1 (sinθ/〖 cos〗θ ) = tan-1 (tan θ) = 𝛉 We assumed that x = a sin θ 𝑥/𝑎 = sin θ sin-1 𝒙/𝒂 = θ Hence, tan-1 𝑥/√(𝑎^2 − 𝑥^2 ) = θ = sin-1 𝒙/𝒂

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Chapter 2 Class 12 Inverse Trigonometric Functions

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.