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Last updated at Dec. 8, 2016 by Teachoo
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Ex 2.2, 9 Write the function in the simplest form: tan-1 𝑥/√(𝑎^2 − 𝑥^2 ) , |x| < a tan-1 𝑥/√(𝑎^2 − 𝑥^2 ) Put x = a sin 𝜃 = tan-1 ((a sinθ)/√(a^2−(a sinθ)^2 )) = tan-1 ((a sinθ)/√(a^2 − a^2 sin2θ)) = tan-1 ((a sinθ)/√(a^2 (1 − sin^2 θ))) = tan-1 ((a sinθ)/(a√(1 − sin^2 θ))) = tan-1 (sinθ/√(cos^2 θ)) = tan-1 (sinθ/〖 cos〗θ ) = tan-1 (tan θ) = θ We assumed that x = a sin θ 𝑥/𝑎 = sin θ sin-1 𝑥/𝑎 = θ Hence, tan-1 𝑥/√(𝑎^2 − 𝑥^2 ) = θ = sin-1 𝑥/𝑎
Ex 2.2
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