
Subscribe to our Youtube Channel - https://you.tube/teachoo
Last updated at Dec. 8, 2016 by Teachoo
Transcript
Ex 2.2, 16 Find the values of sin-1(sin〖2π/3〗 ) Let y = sin-1 (sin 2𝜋/3) sin y = sin 2𝜋/3 sin y = sin (120°) But, range of principal value of sin-1 is [(−π)/2, π/2] i.e. [-90° ,90° ] Hence y = 120° not possible Now, sin y = sin (120°) sin y = sin (180° – 60°) sin y = sin (60°) sin y = sin (60 × 𝜋/180) sin y = sin 𝜋/3 Hence, y = 𝜋/3 Which is in the range of principal value of sin-1 i.e. [(−π)/2, π/2] Hence, sin-1(sin 2π/3) = y = 𝜋/3
Ex 2.2
Ex 2.2, 2 Important Not in Syllabus - CBSE Exams 2021
Ex 2.2, 3 Important Not in Syllabus - CBSE Exams 2021
Ex 2.2, 4 Important Not in Syllabus - CBSE Exams 2021
Ex 2.2, 5 Important Not in Syllabus - CBSE Exams 2021
Ex 2.2, 6 Important Not in Syllabus - CBSE Exams 2021
Ex 2.2, 7 Important Not in Syllabus - CBSE Exams 2021
Ex 2.2, 8 Important Not in Syllabus - CBSE Exams 2021
Ex 2.2, 9 Not in Syllabus - CBSE Exams 2021
Ex 2.2, 10 Important Not in Syllabus - CBSE Exams 2021
Ex 2.2, 11 Not in Syllabus - CBSE Exams 2021
Ex 2.2, 12 Important Not in Syllabus - CBSE Exams 2021
Ex 2.2, 13 Important Not in Syllabus - CBSE Exams 2021
Ex 2.2, 14 Important Not in Syllabus - CBSE Exams 2021
Ex 2.2, 15 Important Not in Syllabus - CBSE Exams 2021
Ex 2.2, 16 Not in Syllabus - CBSE Exams 2021 You are here
Ex 2.2, 17 Not in Syllabus - CBSE Exams 2021
Ex 2.2, 18 Important Not in Syllabus - CBSE Exams 2021
Ex 2.2, 19 Important Not in Syllabus - CBSE Exams 2021
Ex 2.2, 20 Important Not in Syllabus - CBSE Exams 2021
Ex 2.2, 21 Important Not in Syllabus - CBSE Exams 2021
About the Author