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Ex 2.2
Ex 2.2, 2 Important Deleted for CBSE Board 2023 Exams
Ex 2.2, 3 Deleted for CBSE Board 2023 Exams
Ex 2.2, 4 Important Deleted for CBSE Board 2023 Exams
Ex 2.2, 5 Important Deleted for CBSE Board 2023 Exams
Ex 2.2, 6 Deleted for CBSE Board 2023 Exams
Ex 2.2, 7 Important Deleted for CBSE Board 2023 Exams
Ex 2.2, 8 Important Deleted for CBSE Board 2023 Exams
Ex 2.2, 9 Deleted for CBSE Board 2023 Exams
Ex 2.2, 10 Important Deleted for CBSE Board 2023 Exams
Ex 2.2, 11 Deleted for CBSE Board 2023 Exams
Ex 2.2, 12 Important Deleted for CBSE Board 2023 Exams
Ex 2.2, 13 Important Deleted for CBSE Board 2023 Exams
Ex 2.2, 14 Important Deleted for CBSE Board 2023 Exams
Ex 2.2, 15 Important Deleted for CBSE Board 2023 Exams
Ex 2.2, 16 Deleted for CBSE Board 2023 Exams You are here
Ex 2.2, 17 Deleted for CBSE Board 2023 Exams
Ex 2.2, 18 Important Deleted for CBSE Board 2023 Exams
Ex 2.2, 19 (MCQ) Important Deleted for CBSE Board 2023 Exams
Ex 2.2, 20 (MCQ) Important Deleted for CBSE Board 2023 Exams
Ex 2.2, 21 (MCQ) Deleted for CBSE Board 2023 Exams
Last updated at March 16, 2023 by Teachoo
Ex 2.2, 16 Find the values of sin-1(sin〖2π/3〗 ) Let y = sin-1 (sin 2𝜋/3) sin y = sin 2𝜋/3 sin y = sin (120°) But, Range of sin-1 is [(−π)/2, π/2] i.e. [-90° ,90° ] Hence, y = 120° not possible Now, sin y = sin (120°) sin y = sin (180° – 60°) sin y = sin (60°) sin y = sin (60 × 𝜋/180) sin y = sin 𝜋/3 Hence, y = 𝝅/𝟑 Since this is in range of sin-1 i.e. [(−π)/2, π/2] Hence, sin-1(sin 𝟐𝛑/𝟑) = 𝝅/𝟑 (As sin (180 – θ) = sin θ)