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Ex 2.2
Ex 2.2, 2 Important
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Ex 2.2, 16 You are here
Ex 2.2, 17
Ex 2.2, 18 Important
Ex 2.2, 19 (MCQ) Important
Ex 2.2, 20 (MCQ) Important
Ex 2.2, 21 (MCQ)
Last updated at May 12, 2021 by Teachoo
Ex 2.2, 16 Find the values of sin-1(sin〖2π/3〗 ) Let y = sin-1 (sin 2𝜋/3) sin y = sin 2𝜋/3 sin y = sin (120°) But, Range of sin-1 is [(−π)/2, π/2] i.e. [-90° ,90° ] Hence, y = 120° not possible Now, sin y = sin (120°) sin y = sin (180° – 60°) sin y = sin (60°) sin y = sin (60 × 𝜋/180) sin y = sin 𝜋/3 Hence, y = 𝝅/𝟑 Since this is in range of sin-1 i.e. [(−π)/2, π/2] Hence, sin-1(sin 𝟐𝛑/𝟑) = 𝝅/𝟑 (As sin (180 – θ) = sin θ)