Last updated at May 12, 2021 by

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Ex 2.2, 10 Write the function in the simplest form: tan−1 ((3a2x −x3)/(a3 −3ax2)), α > 0; (−a)/√3 ≤ x ≤ a/√3 tan−1 ((3a2x − x3)/(a3 − 3ax2)) Putting x = a tan θ = tan−1 ((3a^2 (a tan θ) − (a tan θ)^3)/(a^3 − 3a (a tan θ)^2 )) = tan−1 ((3a^3 tan θ − a^3 tan^3 θ)/(a^3 − 3 a.a^2 tan^2 θ)) = tan−1 ((a^3 (3 tan θ − tan^3 θ))/(a^3 (1 − 3 tan^2 θ))) = tan−1 ((3 tan θ − tan^3 θ)/(1 − 3tan^2 θ)) = tan−1 (tan 3θ) = 3θ We know x = a tan θ 𝑥/𝑎 = tan θ tan θ = 𝑥/𝑎 θ = tan−1 (𝒙/𝒂) ("Using tan 3x = " (3 tan〖𝑥 − tan3𝑥 〗)/(1 − 3𝑡𝑎𝑛2𝑥)) Hence, tan−1 ((3a2x − x3)/(a3 − 3ax2)) = 3θ = 3 tan−1 𝒙/𝒂 Hence proved

Ex 2.2

Ex 2.2,1
Deleted for CBSE Board 2022 Exams

Ex 2.2, 2 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 3 Deleted for CBSE Board 2022 Exams

Ex 2.2, 4 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 5 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 6 Deleted for CBSE Board 2022 Exams

Ex 2.2, 7 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 8 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 9 Deleted for CBSE Board 2022 Exams

Ex 2.2, 10 Important Deleted for CBSE Board 2022 Exams You are here

Ex 2.2, 11 Deleted for CBSE Board 2022 Exams

Ex 2.2, 12 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 13 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 14 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 15 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 16 Deleted for CBSE Board 2022 Exams

Ex 2.2, 17 Deleted for CBSE Board 2022 Exams

Ex 2.2, 18 Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 19 (MCQ) Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 20 (MCQ) Important Deleted for CBSE Board 2022 Exams

Ex 2.2, 21 (MCQ) Deleted for CBSE Board 2022 Exams

Chapter 2 Class 12 Inverse Trigonometric Functions (Term 1)

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.