Last updated at May 12, 2021 by Teachoo

Transcript

Ex 2.2, 14 If sin ("sin−1 " 1/5 " + cos−1 x" ) = 1 , then find the value of x. Given sin ("sin−1 " 1/5 " + cos−1 x" ) = 1 Putting sin 𝜋/2 = 1 sin ("sin−1 " 1/5 " + cos−1 x" ) = sin π/2 Comparing angles "sin−1 " 1/5 + "cos−1 x" = 𝜋/2 "sin−1 " 1/5 = 𝝅/𝟐 – "cos−1 x" We know that sin"−"1 x + cos"−"1 x = 𝜋/2 sin"−"1 x = 𝜋/2 – cos"−"1 x sin-1 1/5 = sin"−"1 x Thus, we can write 1/5 = x x = 𝟏/𝟓 Hence, x = 1/5

Ex 2.2

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Ex 2.2, 2 Important Deleted for CBSE Board 2022 Exams

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Ex 2.2, 14 Important Deleted for CBSE Board 2022 Exams You are here

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Ex 2.2, 19 (MCQ) Important Deleted for CBSE Board 2022 Exams

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Ex 2.2, 21 (MCQ) Deleted for CBSE Board 2022 Exams

Chapter 2 Class 12 Inverse Trigonometric Functions (Term 1)

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.