Ex 2.2, 14 - Chapter 2 Class 12 Inverse Trigonometric Functions
Last updated at Dec. 24, 2019 by Teachoo
Transcript
Ex2.2, 14 If sin ("sin−1 " 1/5 " + cos−1 x" ) = 1 , then find the value of x. sin ("sin−1 " 1/5 " + cos−1 x" ) = 1 We know that sin 90° = 1 i.e. sin π/2 = 1 Comparing (1) & (2) sin ("sin−1 " 1/5 " + cos−1 x" ) = sin π/2 Comparing angles "sin−1 " 1/5 + "cos−1 x" = 𝜋/2 "sin−1 " 1/5 = 𝜋/2 – "cos−1 x" sin-1 1/5 = sin-1 x 1/5 = x x = 1/5 Hence, x = 1/5
Ex 2.2
Ex 2.2,1
Ex 2.2, 2 Important
Ex 2.2, 3 Important
Ex 2.2, 4 Important
Ex 2.2, 5 Important
Ex 2.2, 6 Important
Ex 2.2, 7 Important
Ex 2.2, 8 Important
Ex 2.2, 9
Ex 2.2, 10 Important
Ex 2.2, 11
Ex 2.2, 12 Important
Ex 2.2, 13 Important
Ex 2.2, 14 Important You are here
Ex 2.2, 15 Important
Ex 2.2, 16
Ex 2.2, 17
Ex 2.2, 18 Important
Ex 2.2, 19 Important
Ex 2.2, 20 Important
Ex 2.2, 21 Important
Chapter 2 Class 12 Inverse Trigonometric Functions
Serial order wise
About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.