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Misc 2 - Find tan-1 (tan 7pi/6) - Chapter 2 Inverse CBSE

Misc. 2 - Chapter 2 Class 12 Inverse Trigonometric Functions - Part 2


Transcript

Misc 2 Find the value of tan−1(tan⁡〖7π/6〗 ) Let y = tan−1(tan⁡〖7π/6〗 ) tan y =〖 tan〗⁡〖7π/6〗 tan y = tan (210°) But, range of of tan-1 is ("−" 𝜋/2 " , " 𝜋/2) i.e. (−90° ,90°) Hence, y = 210° not possible Now, tan y = tan (210°) tan y = tan (180° + 30°) tan y = tan (30°) tan y = tan (𝜋/6) Hence, y = 𝝅/𝟔 Which is in the range of tan-1 i.e. ((−π)/2, π/2) Hence, tan–1(𝐭𝐚𝐧⁡〖𝟑𝛑/𝟒〗 ) = y = 𝝅/𝟔 (As tan (180 + θ) = tan θ)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.