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Last updated at Feb. 13, 2020 by Teachoo

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Misc 2 Find the value of tan−1(tan〖7π/6〗 ) Let y = tan−1(tan〖7π/6〗 ) tan y =〖 tan〗〖7π/6〗 tan y = tan (210°) We know that range of principal value of tan-1 is ("−" 𝜋/2 " , " 𝜋/2) i.e. (−90° ,90°) Hence y = 210° not possible Now, tan y = tan (210°) tan y = tan (180° + 30°) tan y = tan (30°) tan y = tan (30 × 𝜋/180) tan y = tan (𝜋/6) Hence, y = 𝜋/6 Which is in the range of principal value of tan-1 i.e. ((−π)/2, π/2) Hence, tan–1(tan〖3π/4〗 ) = y = 𝝅/𝟔 (As tan (180 + θ) = tan θ)

Miscellaneous

Misc. 1

Misc. 2 Important You are here

Misc. 3 Not in Syllabus - CBSE Exams 2021

Misc. 4 Important Not in Syllabus - CBSE Exams 2021

Misc. 5 Not in Syllabus - CBSE Exams 2021

Misc. 6 Not in Syllabus - CBSE Exams 2021

Misc. 7 Important Not in Syllabus - CBSE Exams 2021

Misc. 8 Important Not in Syllabus - CBSE Exams 2021

Misc. 9 Important Not in Syllabus - CBSE Exams 2021

Misc. 10 Important Not in Syllabus - CBSE Exams 2021

Misc. 11 Important Not in Syllabus - CBSE Exams 2021

Misc 12 Important Not in Syllabus - CBSE Exams 2021

Misc. 13 Important Not in Syllabus - CBSE Exams 2021

Misc. 14 Not in Syllabus - CBSE Exams 2021

Misc. 15 Important Not in Syllabus - CBSE Exams 2021

Misc 16 Important Not in Syllabus - CBSE Exams 2021

Misc. 17 Important Not in Syllabus - CBSE Exams 2021

Chapter 2 Class 12 Inverse Trigonometric Functions

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.