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Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class


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Misc 3 Prove 2 sin-1 3/5 = tan-1 24/7 We need to convert LHS in form tan-1 Converting sin-1 (πŸ‘/πŸ“) to tan-1 Let x = sin-1 (3/5) sin x = 3/5 Now, cos x = √(1βˆ’π‘ π‘–π‘›2 π‘₯) = √(1 βˆ’ (3/5)^2 ) = √(1 βˆ’ 9/25) = √((25 βˆ’ 9)/25) = √(16/25) = 4/5 Thus, tan x = sin⁑π‘₯/cos⁑π‘₯ tan x = (3/5)/(4/5) tan x = 3/4 x = tan–1 πŸ‘/πŸ’ Solving L.H.S 2 sin–1 πŸ‘/πŸ“ = 2x = 2 tan-1 (3/4) Using 2tan-1 x = tan-1 (πŸπ’™/(𝟏 βˆ’ π’™πŸ)) = tan-1 (2(3/4)/(1 βˆ’ (3/4)2)) = tan-1 ((3/2)/(1 βˆ’ 9/16)) = tan-1 ((3/2)/( (16 βˆ’ 9)/16)) = tan-1 ((3/2)/( 7/16)) = tan-1 (3/2Γ—16/7) = tan-1 (πŸπŸ’/πŸ•) = R.H.S. Hence L.H.S. = R.H.S Hence proved

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.