Misc. 23 (MCQ) - Chapter 6 Class 12 Application of Derivatives (Term 1)

Last updated at Aug. 9, 2021 by

Misc 23 - Normal to x2 = 4y passing (1,2) is (a) x + y = 3

Misc. 23 - Chapter 6 Class 12 Application of Derivatives - Part 2

Misc. 23 - Chapter 6 Class 12 Application of Derivatives - Part 3

Transcript

Misc 23 The normal to the curve 𝑥^2=4𝑦 passing (1, 2) is (𝐴) 𝑥 + 𝑦 = 3 (𝐵) 𝑥 – 𝑦 = 3 (𝐶) 𝑥 + 𝑦 = 1 (𝐷) 𝑥 – 𝑦 = 1Since (1, 2) lies on normal, it will satisfy its equation Option 1: 𝒙+𝒚=𝟑 Putting 𝑥=1 & 𝑦=2 in equation 1 +2=3 3=3 This is true So, it is the equation of Normal Option 2: 𝒙−𝒚=𝟑 Putting 𝑥=1 & 𝑦=2 in equation 1 −2=3 −1=3 This is false So, it is not equation of Normal Option 3: 𝒙+𝒚=𝟏 Putting 𝑥=1 & 𝑦=2 in equation 1 +2=1 3=1 This is false So, it is not equation of Normal Option 4: 𝒙−𝒚=𝟏 Putting 𝑥=1 & 𝑦=2 in equation 1 −1=1 0=1 This is false So, it is not equation of Normal Hence, Correct Answer is (A)

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.