Misc 23 - Normal to x2 = 4y passing (1,2) is (a) x + y = 3

Misc. 23 - Chapter 6 Class 12 Application of Derivatives - Part 2
Misc. 23 - Chapter 6 Class 12 Application of Derivatives - Part 3

Something went wrong!

The video couldn't load due to a technical hiccup.
But don't worry — our team is already on it, and we're working hard to get it back up ASAP.

Thanks for bearing with us!

Share on WhatsApp

Transcript

Misc 23 The normal to the curve π‘₯^2=4𝑦 passing (1, 2) is (𝐴) π‘₯ + 𝑦 = 3 (𝐡) π‘₯ – 𝑦 = 3 (𝐢) π‘₯ + 𝑦 = 1 (𝐷) π‘₯ – 𝑦 = 1Since (1, 2) lies on normal, it will satisfy its equation Option 1: 𝒙+π’š=πŸ‘ Putting π‘₯=1 & 𝑦=2 in equation 1 +2=3 3=3 This is true So, it is the equation of Normal Option 2: π’™βˆ’π’š=πŸ‘ Putting π‘₯=1 & 𝑦=2 in equation 1 βˆ’2=3 βˆ’1=3 This is false So, it is not equation of Normal Option 3: 𝒙+π’š=𝟏 Putting π‘₯=1 & 𝑦=2 in equation 1 +2=1 3=1 This is false So, it is not equation of Normal Option 4: π’™βˆ’π’š=𝟏 Putting π‘₯=1 & 𝑦=2 in equation 1 βˆ’1=1 0=1 This is false So, it is not equation of Normal Hence, Correct Answer is (A)

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo