Misc 23 - Normal to x2 = 4y passing (1,2) is (a) x + y = 3 - Finding equation of tangent/normal when point and curve is given

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  1. Chapter 6 Class 12 Application of Derivatives
  2. Serial order wise

Transcript

Misc. 23 The normal to the curve 2 =4 passing (1,2) is ( ) + = 3 ( ) = 3 ( ) + = 1 ( ) = 1 Since (1, 2) lies on normal, it will satisfy its equation Option 1 Equation of Normal is + =3 Putting =1 & =2 in equation + =3 1+2=3 3=3 Thus, 1 , 2 Satisfy the Equation of Normal Hence + =3 is Required Equation of Normal Option 2 If equation of Normal is =3 Putting =1 & =2 in equation =3 1 2=3 1=3 But 1 3 Hence =3 is not the equation of Normal Option 3 If Equation of Normal is + =1 Putting =1 & =2 in equation + =1 1+2=1 3=1 But, 3 1 Hence + =1 is not Required Equation of Normal Option 4 If Equation of Normal is =1 Putting =1 & =2 in equation =1 1 2=1 1=1 Since 1 1 Hence =1 is not Required Equation of Normal Hence Correct Answer is (A)

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