# Misc 20 - Chapter 6 Class 12 Application of Derivatives

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Misc 20 The slope of the tangent to the curve x = t2 + 3t 8, y = 2t2 2t 5 at the point (2, 1) is (A) 22 7 (B) 6 7 (C) 7 6 (D) 6 7 We need to find slope of tangent at (2, -1) We know that slope of tangent is = Thus, = = 4 2 2 + 3 Now we need to find value of t Given point is (2, 1) Putting = 2 & = 1 in the curve Since t = 2 is common in both parts So, we will calculate = 4 2 2 3 at t = 2 At t = 2 = 4 2 2 + 3 = 4 2 2 2 2 + 3 = 8 2 4 +3 = 6 7 Hence the correct answer is (B)

Chapter 6 Class 12 Application of Derivatives

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.