Misc 20 - Chapter 6 Class 12 Application of Derivatives
Last updated at May 29, 2018 by Teachoo
Transcript
Misc 20 The slope of the tangent to the curve x = t2 + 3t 8, y = 2t2 2t 5 at the point (2, 1) is (A) 22 7 (B) 6 7 (C) 7 6 (D) 6 7 We need to find slope of tangent at (2, -1) We know that slope of tangent is = Thus, = = 4 2 2 + 3 Now we need to find value of t Given point is (2, 1) Putting = 2 & = 1 in the curve Since t = 2 is common in both parts So, we will calculate = 4 2 2 3 at t = 2 At t = 2 = 4 2 2 + 3 = 4 2 2 2 2 + 3 = 8 2 4 +3 = 6 7 Hence the correct answer is (B)
Chapter 6 Class 12 Application of Derivatives
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.