Subscribe to our Youtube Channel - https://you.tube/teachoo

Last updated at Jan. 7, 2020 by Teachoo

Transcript

Misc 14 Find the absolute maximum and minimum values of the function f given by f (π₯) = cos2 π₯ + sinβ‘π₯, π₯ β [0, π ] f(π₯)=cos^2 π₯+sin π₯ , π₯ β [0 , π] Finding fβ(π) f(π₯)=cos^2 π₯+sin π₯ fβ(π₯)= π(cos^2β‘γπ₯ + sinβ‘π₯ γ )/ππ₯ = 2cos π₯. π(cos π₯)/ππ₯ + cos π₯ = 2cos π₯(βsin π₯)+cosβ‘π₯ = cos π₯ (β2sin π₯+1) Putting fβ(π) = 0 cos π₯ (β2 sinβ‘γπ₯+1γ )=0 π₯ = π/6 & (π )/2 are Critical points. cos π₯ = 0 cos π₯ = 0 cos π₯ = cos π/2 π₯ = π/2 β 2 sin π₯ + 1 = 0 β 2 sin π₯ = β1 sin π₯ = (β1)/(β2) sin π₯ = 1/2 sin π₯ = sin π/6 π₯ = π/6 Since our interval is π₯ β [0, π ] Critical points are π₯=0, π/6 , π/2 , π Hence Absolute maximum value = π/π & Absolute minimum value = 1

Miscellaneous

Misc 1
Important

Misc 2 Important

Misc 3 Important

Misc 4

Misc 5 Important

Misc 6 Important

Misc 7

Misc 8 Important

Misc 9 Important

Misc 10

Misc 11 Important

Misc 12 Important

Misc 13 Important

Misc 14 Important You are here

Misc 15 Important

Misc 16 Important

Misc 17 Important

Misc 18 Important

Misc. 19

Misc 20 Important

Misc 21 Important

Misc 22

Misc. 23 Important

Misc 24 Important

Chapter 6 Class 12 Application of Derivatives

Serial order wise

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.