Check Full Chapter Explained - Continuity and Differentiability - Application of Derivatives (AOD) Class 12

Last updated at Dec. 14, 2019 by Teachoo

Check Full Chapter Explained - Continuity and Differentiability - Application of Derivatives (AOD) Class 12

Transcript

Misc 22 The normal at the point (1,1) on the curve 2 + 2 =3 is + = 0 ( ) = 0 ( ) + +1 = 0 ( ) = 1 Since (1, 1) lies on normal, it will satisfy its equation Option 1 Equation of Normal is + =0 Putting =1 & =1 in equation 1 +1=0 2=0 2 0 + =0 is not equation of Normal Option 2 If Equation of Normal is = 0 Putting =1 & =1 in equation =0 1 1=0 0=0 Since Point 1 , 1 Satisfying the Equation of Normal Hence, required Equation of Normal is =0 Option 3 If Equation of Normal is + +1=0 Putting =1 & =1 in equation + +1=0 1+1+1=0 3=0 But 3 0 + +1=0 is not Required Equation of Normal Option 4 If Equation of Normal is =1 Putting =1 & =1 in equation 1 1=1 0=1 But 0 1 =1 is not Required Equation of Normal Hence, Correct Answer is (B)

Miscellaneous

Misc 1
Important
Not in Syllabus - CBSE Exams 2021

Misc 2 Important

Misc 3 Important Not in Syllabus - CBSE Exams 2021

Misc 4

Misc 5 Important

Misc 6 Important

Misc 7

Misc 8 Important

Misc 9 Important

Misc 10

Misc 11 Important

Misc 12 Important

Misc 13 Important

Misc 14 Important

Misc 15 Important

Misc 16 Important

Misc 17 Important

Misc 18 Important

Misc. 19 Not in Syllabus - CBSE Exams 2021

Misc 20 Important

Misc 21 Important

Misc 22 You are here

Misc. 23 Important

Misc 24 Important

Chapter 6 Class 12 Application of Derivatives

Serial order wise

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.