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Miscellaneous
Last updated at April 16, 2024 by Teachoo
Misc 22 The normal at the point (1,1) on the curve 2π¦+π₯^2=3 is (π΄) π₯ + π¦ = 0 (π΅) π₯ β π¦ = 0 (πΆ) π₯ + π¦ +1 = 0 (π·) π₯ β π¦ = 1Since (1, 1) lies on normal, it will satisfy its equation Option 1: π+π=π Putting π₯=1 & π¦=1 in equation 1 +1=0 2=0 This is false So, it is not equation of Normal Since (1, 1) lies on normal, it will satisfy its equation Option 1: π+π=π Putting π₯=1 & π¦=1 in equation 1 +1=0 2=0 This is false So, it is not equation of Normal Option 4: πβπ=π Putting π₯=1 & π¦=1 in equation 1 β1=1 0=1 This is false So, it is not equation of Normal Hence, Correct Answer is (B)