This question is similar to Chapter 8 Class 12 Application of Integrals - Ex 8.1

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Question 23 (B) Find out the area of shaded region in the enclosed figure. Let’s redraw the figure The curve is 𝒙^𝟐=π’š We have to find area between y = 0 and y = 4 ∴ We have to find area of BNO Area of BNO = ∫_𝟎^πŸ’β–’π’™ π’…π’š We know that π‘₯^2=𝑦 Taking square root on both sides 𝒙="Β±" βˆšπ’š Since, BNO is in 1st Quadrant We take positive value of x ∴ 𝒙=βˆšπ’š Area of BCFE = ∫_0^4β–’π‘₯ 𝑑𝑦 = ∫_𝟎^πŸ’β–’βˆšπ’š π’…π’š = ∫_0^4β–’γ€–(𝑦)^(1/2) 𝑑𝑦〗 = [𝑦^(3/2)/(3/2)]_0^4 = 2/3 [𝑦^(3/2) ]_2^4 = 𝟐/πŸ‘ [(πŸ’)^(πŸ‘/𝟐 )βˆ’(𝟎)^(πŸ‘/𝟐) ] = 2/3 [(4)^(3/2 ) ] = 𝟐/πŸ‘ [𝟐^(𝟐 Γ—πŸ‘/𝟐) ] = 2/3 Γ— 2^3 = (2 Γ— 8)/3 = πŸπŸ”/πŸ‘ Thus, Area = πŸπŸ”/πŸ‘ square units Area of BCFE = ∫_0^4β–’π‘₯ 𝑑𝑦 = ∫_𝟎^πŸ’β–’βˆšπ’š π’…π’š = ∫_0^4β–’γ€–(𝑦)^(1/2) 𝑑𝑦〗 = [𝑦^(3/2)/(3/2)]_0^4 = 2/3 [𝑦^(3/2) ]_2^4 = 𝟐/πŸ‘ [(πŸ’)^(πŸ‘/𝟐 )βˆ’(𝟎)^(πŸ‘/𝟐) ] = 2/3 [(4)^(3/2 ) ] = 𝟐/πŸ‘ [𝟐^(𝟐 Γ—πŸ‘/𝟐) ]

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo