This question is similar to Chapter 2 Class 12 Inverse Trigonometric Functions  - Ex 2.1

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https://www.teachoo.com/3041/676/Ex-2.1--6---Find-principal-value-of-tan-1-(-1)---Chapter-2-Inverse/category/Ex-2.1/

 

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Question 21 (A) Evaluate tan(tan^(βˆ’1) (βˆ’1)+πœ‹/3)We have to find 𝐭𝐚𝐧(〖𝒕𝒂𝒏〗^(βˆ’πŸ) (βˆ’πŸ)+𝝅/πŸ‘) Let’s find tan^(βˆ’1) (βˆ’1) first 〖𝒕𝒂𝒏〗^(βˆ’πŸ) (βˆ’πŸ) Let y = tanβˆ’1 (βˆ’1) We know that tanβˆ’1 (βˆ’x) = βˆ’ tan βˆ’1 x y = βˆ’ tanβˆ’1 (1) y = βˆ’ 𝝅/πŸ’ Since Range of tanβˆ’1 is (βˆ’Ο€/2,Ο€/2) Hence, tanβˆ’1 (βˆ’1) = βˆ’ 𝝅/πŸ’ is correct Now, 𝒕𝒂𝒏(〖𝒕𝒂𝒏〗^(βˆ’πŸ) (βˆ’πŸ)+𝝅/πŸ‘) =π‘‘π‘Žπ‘›((βˆ’πœ‹)/4+πœ‹/3) =𝒕𝒂𝒏(𝝅/πŸ‘βˆ’π…/πŸ’) Using π‘‘π‘Žπ‘›(π΄βˆ’π΅)=(π‘‘π‘Žπ‘›β‘π΄ βˆ’ π‘‘π‘Žπ‘›β‘π΅)/(1 + π‘‘π‘Žπ‘›β‘π΄ π‘‘π‘Žπ‘›β‘π΅ ) =(π‘‘π‘Žπ‘›(πœ‹/3) βˆ’ tan⁑(πœ‹/4))/(1 + π‘‘π‘Žπ‘›(πœ‹/3) tan⁑(πœ‹/4) ) =(√3 βˆ’ 1)/(1 + √3 Γ— 1) =(√3 βˆ’ 1)/(1 + √3 ) =(βˆšπŸ‘ βˆ’ 𝟏)/(βˆšπŸ‘ + 𝟏)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo