

Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Ex 8.2
Ex 8.2, 2
Ex 8.2, 3 Important
Ex 8.2, 4
Ex 8.2, 5 (a)
Ex 8.2, 5 (b) Important
Ex 8.2, 5 (c)
Ex 8.2, 6
Ex 8.2, 7 Important
Ex 8.2, 8
Ex 8.2, 9 Important
Ex 8.2, 10
Ex 8.2, 11 Important
Ex 8.2, 12
Ex 8.2, 13
Ex 8.2, 14 Important
Ex 8.2, 15
Ex 8.2, 16 Important
Ex 8.2, 17 Important
Ex 8.2, 18 Important
Ex 8.2, 19
Ex 8.2, 20
Ex 8.2, 21
Ex 8.2, 22 Important
Ex 8.2, 23 Important
Ex 8.2, 24
Ex 8.2, 25
Ex 8.2, 26 Important
Ex 8.2, 27 Important You are here
Ex 8.2, 28
Ex 8.2, 29 Important
Ex 8.2, 30 Important
Ex 8.2, 31
Ex 8.2, 32 Important
Last updated at May 29, 2023 by Teachoo
Ex9.3, 27 Find the value of n so that (π^(π + 1) +π^(π + 1))/(π^(π ) +π^π ) may be the geometric mean between a and b. We know that geometric mean between a & b is a & b = βab It is given that G.M. between a & b = (π^(π + 1) +π^(π + 1))/(π^(π ) +π^(π ) ) βab = (π^(π + 1) +π^(π + 1))/(π^(π ) +π^(π ) ) γ"(ab)" γ^(1/2) = (π^(π + 1) +π^(π + 1))/(π^(π ) +π^(π ) ) γ"(ab)" γ^(1/2) (an +bn) = an + 1 + bn + 1 γ"a" γ^(1/2) π^(1/2) (an +bn) = an + 1 + bn + 1 γ"a" γ^(1/2) an π^(1/2) + γ"a" γ^(1/2) bn π^(1/2) = an + 1 + bn + 1 π^(1/2 + π ) π^(1/2) + γ"a" γ^(1/2) π^(1/2 + π )= an + 1 + bn + 1 π^(1/2 + π ) π^(1/2) β an + 1 = bn + 1 β γ"a" γ^(1/2) π^(1/2 + π ) π^(1/2 + π ) π^(1/2) β π^(π + 1/2 + 1/2) = π^(π + 1/2 + 1/2) β π^(1/2) π^(1/2 + π ) π^(1/2 + π ) [π^(1/2) β π^(1/2)] = π^(π + 1/2 ) [π^(1/2) β π^(1/2)] π^(1/2 + π )= π^(π + (1 )/2 "[" π^(1/2) " β " π^(1/2) "] " )/(π^(1/2) " β " π^(1/2) ) π^(1/2 + π )= π^(π +1/2) (π/π)^(1/2 + π) = 1 (π/π)^(1/2 + π)= (π/π)^0 Comparing powers 1/2 + n = 0 n = β 1/2 Hence value of n is - 1/2