Ex 9.3, 26 - Class 11

Transcript

Ex 9.3, 26 Insert two numbers between 3 and 81 so that the resulting sequence is G.P. We know that to insert n numbers between a & b Common ratio r = (𝑏/𝑎)^(1/(𝑛+1)) We need to insert 2 numbers between 3 & 81 Here a = 3 & b = 81 & n = number of terms to be inserted = 2 So r = (81/3)^(1/(2+1)) = 〖(27)〗^(1/3) = 〖(3)〗^(3 × 1/3 ) = 3 Ex 9.3, 26 Insert two numbers between 3 and 81 so that the resulting sequence is G.P. We know that to insert n numbers between a & b Common ratio r = (𝑏/𝑎)^(1/(𝑛+1)) We need to insert 2 numbers between 3 & 81 Here a = 3 & b = 81 & n = number of terms to be inserted = 2 So r = (81/3)^(1/(2+1)) = 〖(27)〗^(1/3) = 〖(3)〗^(3 × 1/3 ) = 3 Thus, a = 3 , r = 3, b = 81 Inserting numbers Hence the two numbers inserted between 1 & 81 are 9 & 27 Thus, a = 3 , r = 3, b = 81 Inserting numbers Hence the two numbers inserted between 1 & 81 are 9 & 27