Check sibling questions

Ex 9.3, 3 - Chapter 9 Class 11 Sequences and Series (Term 1)

Last updated at March 9, 2017 by

Ex 9.3, 3 - The 5th, 8th and 11th terms of GP are p, q, s - Ex 9.3

Ex 9.3, 3 - Chapter 9 Class 11 Sequences and Series - Part 2
Ex 9.3, 3 - Chapter 9 Class 11 Sequences and Series - Part 3

This video is only available for Teachoo black users

Subscribe Now

Transcript

Ex 9.3, 3 The 5th, 8th and 11th terms of a G.P. are p, q and s, respectively. Show that q2 = ps. We know that an = arn – 1 where an = nth term of GP n is the number of terms a is the first term r is the common ratio Here, 5th term is p i.e. a5 = p Putting n = 5 in an formula p = ar5–1 p = ar4 Also, 8th term is q i.e. a8 = q Putting n = 8 in an formula q = ar8 – 1 q = ar7 Also, 11th term is s i.e. a11 = s Putting n = 11 in an formula s = ar11 – 1 s = ar10 We need to show that q2 = ps. Taking L.H.S q2 Putting value q = ar7 from (2) = (ar7)2 = a2r14 Now, solving R.H.S ps Putting p = ar4 , s = ar10 from (1)& (3) = (ar4) (ar10) = (a × a)(r10 × r4) = a2r14 = L.H.S Thus, L.H.S = R.H.S Hence proved

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.