

Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Ex 8.2
Ex 8.2, 2
Ex 8.2, 3 Important
Ex 8.2, 4
Ex 8.2, 5 (a)
Ex 8.2, 5 (b) Important
Ex 8.2, 5 (c)
Ex 8.2, 6
Ex 8.2, 7 Important
Ex 8.2, 8
Ex 8.2, 9 Important
Ex 8.2, 10
Ex 8.2, 11 Important
Ex 8.2, 12
Ex 8.2, 13
Ex 8.2, 14 Important
Ex 8.2, 15
Ex 8.2, 16 Important
Ex 8.2, 17 Important
Ex 8.2, 18 Important
Ex 8.2, 19
Ex 8.2, 20
Ex 8.2, 21
Ex 8.2, 22 Important
Ex 8.2, 23 Important You are here
Ex 8.2, 24
Ex 8.2, 25
Ex 8.2, 26 Important
Ex 8.2, 27 Important
Ex 8.2, 28
Ex 8.2, 29 Important
Ex 8.2, 30 Important
Ex 8.2, 31
Ex 8.2, 32 Important
Last updated at May 29, 2023 by Teachoo
Ex 8.2, 23 If the first and the nth term of a G.P. are a and b, respectively, and if P is the product of n terms, prove that P2 = (ab)n. Let a be the first term of G.P & r be the common ratio of G.P Given, first term of G.P = a We know that nth term of G.P = arn-1 b = arn-1 Now P is the product of n terms P = a1 a2 a3 an = a ar ar2 ar3 arn 1 = (a a a) (r r2 rn 1) = an ^(1+2+ +( 1)) = an ^(( ( 1))/2) Thus, P = an ^(( ( 1))/2) We need to prove P2 = (ab)n. Taking L.H.S P2 = ("an " r^((n(n 1))/2) )^2 = ( ^( 2) " " r^((n(n 1))/2 2) ) = ( ^2 " " r^(n(n 1)) ) = ( ^2 " " r^((n 1)) )^ = ( r^((n 1)) )^ = ( ( r^((n 1) )))^ = ( )^ = ( )^ = R.H.S Thus, P2 = ( )^ Hence proved