Maths Crash Course - Live lectures + all videos + Real time Doubt solving!
Ex 9.3
Ex 9.3, 2
Ex 9.3, 3 Important
Ex 9.3, 4
Ex 9.3, 5 (a)
Ex 9.3, 5 (b) Important
Ex 9.3, 5 (c)
Ex 9.3, 6
Ex 9.3, 7 Important
Ex 9.3, 8
Ex 9.3, 9 Important
Ex 9.3, 10
Ex 9.3, 11 Important
Ex 9.3, 12
Ex 9.3, 13
Ex 9.3, 14 Important
Ex 9.3, 15
Ex 9.3, 16 Important
Ex 9.3, 17 Important
Ex 9.3, 18 Important
Ex 9.3, 19
Ex 9.3, 20
Ex 9.3, 21
Ex 9.3, 22 Important
Ex 9.3, 23 Important
Ex 9.3, 24 You are here
Ex 9.3, 25
Ex 9.3, 26 Important
Ex 9.3, 27 Important
Ex 9.3, 28
Ex 9.3, 29 Important
Ex 9.3, 30 Important
Ex 9.3, 31
Ex 9.3, 32 Important
Ex 9.3
Last updated at May 29, 2018 by Teachoo
Maths Crash Course - Live lectures + all videos + Real time Doubt solving!
We need to show ratio of the sum of n terms of GP & sum of terms from (n + 1)th to 2nth term i.e. we need to calculate ( )/( ( + 1) (2 ) ) Putting values from (1) & (2) = (( a(1 ^ ))/((1 r)))/(( a)/((1 r))( ^ ^2 )" " ) = (( a(1 ^ ))/((1 r)))/(( a)/((1 r) ) ^ (1 ^ )" " ) = (( a(1 ^ ))/((1 r)))/ (( a(1 ^ ))/((1 r))) = ( a(1 ^ ))/(rn(1 ^ )) ( 1 r)/(1 r) Ex 9.3, 24 Show that the ratio of the sum of first n terms of a G.P. to the sum of terms from (n+1)th to (2n)th term is ( 1)/rn Ex 9.3, 24 Show that the ratio of the sum of first n terms of a G.P. to the sum of terms from (n+1)th to (2n)th term is ( 1)/rn We need to show ratio of the sum of n terms of GP & sum of terms from (n + 1)th to 2nth term i.e. we need to calculate ( )/( ( + 1) (2 ) ) Putting values from (1) & (2) = (( a(1 ^ ))/((1 r)))/(( a)/((1 r))( ^ ^2 )" " ) = (( a(1 ^ ))/((1 r)))/(( a)/((1 r) ) ^ (1 ^ )" " ) = (( a(1 ^ ))/((1 r)))/ (( a(1 ^ ))/((1 r))) = ( a(1 ^ ))/(rn(1 ^ )) ( 1 r)/(1 r) = 1/