This question is similar to Chapter 10 Class 12 Vector Algebra - Ex 10.3

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[Class 12 SQP] Question 24 (A) - If vectors š‘Žāƒ— = 2ıĢ‚ + 2ȷĢ‚ + 3k Ģ‚, š‘ - CBSE Class 12 Sample Paper for 2025 Boards

part 2 - Question 24 (A) - CBSE Class 12 Sample Paper for 2025 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12

 

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Question 24 (A) If vectors š‘Ž āƒ—=2š‘– ˆ+2šš„ ˆ+3š‘˜ ˆ,š‘ āƒ—=āˆ’šš¤ ˆ+2šš„ ˆ+š‘˜ ˆ and š‘ āƒ—=3š‘– ˆ+šš„ ˆ are such that š‘ āƒ—+šœ†š‘ āƒ— is perpendicular to š‘Ž āƒ—, then find the value of šœ†.Given š‘Ž āƒ— = 2š‘– Ģ‚ + 2š‘— Ģ‚ + 3š‘˜ Ģ‚ š‘ āƒ— = āˆ’š‘– Ģ‚ + 2š‘— Ģ‚ + š‘˜ Ģ‚ š‘ āƒ— = 3š‘– Ģ‚ + š‘— Ģ‚ Now, (š’ƒ āƒ— + šœ†š’„ āƒ—) = (āˆ’š‘– Ģ‚ + 2š‘— Ģ‚ + š‘˜ Ģ‚) + šœ† (3š‘– Ģ‚ + š‘— Ģ‚) = āˆ’š‘– Ģ‚ + 2š‘— Ģ‚ + š‘˜ Ģ‚ + 3šœ†š‘– Ģ‚ + šœ†š‘— Ģ‚ = (3šœ† āˆ’ 1) š’Š Ģ‚ + (2 + šœ†) š’‹ Ģ‚ + š’Œ Ģ‚ Since (š’ƒ āƒ— + šœ†š’„ āƒ—) is perpendicular to š’‚ āƒ— And, since Dot product of perpendicular vectors is 0 Therefore, (š’ƒ āƒ— + šœ†š’„ āƒ—). š’‚ āƒ— = 0 ["(3šœ† āˆ’ 1) " š‘– Ģ‚" + (2 + šœ†) " š‘— Ģ‚" + " š‘˜ Ģ‚ ] . (2š‘– Ģ‚ + 2š‘— Ģ‚ + 3š‘˜ Ģ‚) = 0 (3šœ† āˆ’ 1) Ɨ 2 + (2 + šœ†) Ɨ 2 + 1 Ɨ 3 = 0 6šœ† āˆ’ 2 + 4 + 2šœ† + 3 = 0 8šœ† + 5 = 0 8šœ† = āˆ’5 šœ† = (āˆ’šŸ“)/šŸ–

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