The function f (x) = cot x is discontinuous on the set

(A) {x=nπ:n∈ Z}                

(B) {x=2nπ:n∈ Z}  

(C) {x= (2n+1)  π/2   ; n ∈z}                      

(D) {x= n π/2   ; n ∈z}

This question is similar to Example 18 - Chapter 5 Class 12 - Continuity and Differentiability

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  1. Chapter 5 Class 12 Continuity and Differentiability (Term 1)
  2. Serial order wise

Transcript

Question 16 The function f (x) = cot x is discontinuous on the set (A) {๐‘ฅ=๐‘›๐œ‹:๐‘›โˆˆ๐’} (B) {๐‘ฅ=2๐‘›๐œ‹:๐‘›โˆˆ๐’} (C) {๐‘ฅ=(๐Ÿ๐’+๐Ÿ) ๐…/๐Ÿ ;๐‘›โˆˆ๐’›} (D) {๐‘ฅ=๐’๐…/๐Ÿ ;๐‘›โˆˆ๐’›} Let ๐‘“(๐‘ฅ) = c๐‘œ๐‘กโก๐‘ฅ ๐’‡(๐’™) = ๐’„๐’๐’”โก๐’™/๐’”๐’Š๐’โก๐’™ Here, ๐‘“(๐‘ฅ) is defined for all real number except ๐’”๐’Š๐’โก๐’™ = 0 i.e. for all x except x = ๐’๐… Thus, cotโก๐‘ฅ is discontinuous on the set {๐’™=๐’๐…:๐’โˆˆ๐’} So, the correct answer is (A)

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.