NCERT Exemplar - MCQs

Chapter 5 Class 12 Continuity and Differentiability
Serial order wise

## (D) 3/4

This question is similar to Question 16 (Or 2nd) - CBSE Class 12 - Sample Paper for 2019 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards

### Transcript

Question 22 If x = t2, y = t3, then (๐^2 ๐ฆ)/(๐๐ฅ^2 ) is (A) 3/2 (B) 3/4๐ก (C) 3/2๐ก (D) 3/4 ๐ฅ=๐ก^2 & ๐ฆ=๐ก^3 Finding ๐๐/๐๐ ๐๐/๐๐=(๐๐/๐๐)/(๐๐/๐๐) Finding ๐๐/๐๐ ๐ฆ=๐ก^3 ๐๐ฆ/๐๐ก=(๐(๐ก^3))/๐๐ก ๐๐/๐๐=๐๐^๐ Finding ๐๐/๐๐ ๐ฅ =๐ก^2 ๐๐ฅ/๐๐ก=(๐(๐ก^2))/๐๐ก ๐๐/๐๐=๐๐ Now, ๐๐/๐๐=(๐๐/๐๐)/(๐๐/๐๐) =(3๐ก^2)/2๐ก =๐๐/๐ Finding (๐^๐ ๐)/(๐๐^๐ ) (๐^๐ ๐)/(๐๐^๐ )=๐(3๐ก/2)/๐๐ฅ =๐(3๐ก/2)/๐๐กร๐๐/๐๐ =3/2ร๐๐ก/๐๐ฅ =3/2ร๐/(๐๐/๐๐) Putting ๐๐ฅ/๐๐ก=2๐ก =3/2ร๐/๐๐ =๐/๐๐ So, the correct answer is (B)