NCERT Exemplar - MCQs

Chapter 5 Class 12 Continuity and Differentiability
Serial order wise

(D) 3/4

This question is similar to Question 16 (Or 2nd) - CBSE Class 12 - Sample Paper for 2019 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards

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Transcript

Question 24 If x = t2, y = t3, then (π^2 π¦)/(ππ₯^2 ) is (A) 3/2 (B) 3/4π‘ (C) 3/2π‘ (D) 3/4 π₯=π‘^2 & π¦=π‘^3 Finding ππ/ππ ππ/ππ=(ππ/ππ)/(ππ/ππ) Finding ππ/ππ π¦=π‘^3 ππ¦/ππ‘=(π(π‘^3))/ππ‘ ππ/ππ=ππ^π Finding ππ/ππ π₯ =π‘^2 ππ₯/ππ‘=(π(π‘^2))/ππ‘ ππ/ππ=ππ Now, ππ/ππ=(ππ/ππ)/(ππ/ππ) =(3π‘^2)/2π‘ =ππ/π Finding (π^π π)/(ππ^π ) (π^π π)/(ππ^π )=π(3π‘/2)/ππ₯ =π(3π‘/2)/ππ‘Γππ/ππ =3/2Γππ‘/ππ₯ =3/2Γπ/(ππ/ππ) Putting ππ₯/ππ‘=2π‘ =3/2Γπ/ππ =π/ππ So, the correct answer is (B)