The function f (x) = {8(sin⁑x/x " + cos x, if x " β‰ " 0" k", if x " =" 0" )─ is continuous at x = 0, then the value of k is

(A) 3Β  Β Β Β 

(B) 2

(C) 1Β  Β  Β 

(D) 1.5

Β 

This question is similar to Ex 5.1, 18 - Chapter 5 Class 12 - Continuity and Differentiability

MCQ Class 12 - The function f(x) = { sin x/x + cos x, if x β‰  0, k, if - NCERT Exemplar - MCQs

part 2 - Question 1 - NCERT Exemplar - MCQs - Serial order wise - Chapter 5 Class 12 Continuity and Differentiability
part 3 - Question 1 - NCERT Exemplar - MCQs - Serial order wise - Chapter 5 Class 12 Continuity and Differentiability

Share on WhatsApp

Transcript

Question 1 The function f (x) = {β– 8(sin⁑π‘₯/π‘₯ " + cos x, if x " β‰ " 0" @π‘˜ ", if x " =" 0" )─ is continuous at x = 0, then the value of k is (A) 3 (B) 2 (C) 1 (D) 1.5 At 𝒙 = 0 f(x) is continuous at π‘₯=0 if L.H.L = R.H.L = 𝑓(0) if if lim┬(xβ†’0^βˆ’ ) 𝑓(π‘₯) = lim┬(xβ†’0^+ ) 𝑓(π‘₯) = 𝑓(0) LHL at x β†’ 0 (π’π’Šπ’Ž)┬(π±β†’πŸŽ^βˆ’ ) f(x) = lim┬(hβ†’0) f(0 βˆ’ h) = (π’π’Šπ’Ž)┬(π‘β†’πŸŽ) f(βˆ’h) = lim┬(hβ†’0) sin⁑〖(βˆ’β„Ž)γ€—/((βˆ’β„Ž)) " + cos (βˆ’ h)" = (π’π’Šπ’Ž)┬(π‘β†’πŸŽ) γ€–βˆ’π’”π’Šπ’γ€—β‘π’‰/(βˆ’π’‰) " +" (π’π’Šπ’Ž)┬(π‘β†’πŸŽ) " cos h" = lim┬(hβ†’0) sinβ‘β„Ž/β„Ž " + " (π‘™π‘–π‘š)┬(β„Žβ†’0) " cos h" Using lim┬(xβ†’0) sin⁑π‘₯/π‘₯=1 = 1 + "cos 0" = 1 + 1 = 2 RHL at x β†’ 0 (π’π’Šπ’Ž)┬(π’™β†’πŸŽ^+ ) f(x) = lim┬(hβ†’0) f(0 + h) = (π’π’Šπ’Ž)┬(π‘β†’πŸŽ) f(h) = lim┬(hβ†’0) sinβ‘β„Ž/β„Ž " + cos h" = (π’π’Šπ’Ž)┬(π‘β†’πŸŽ) π’”π’Šπ’β‘π’‰/𝒉 " + " (π’π’Šπ’Ž)┬(π‘β†’πŸŽ) " cos h" Using lim┬(xβ†’0) sin⁑π‘₯/π‘₯=1 = 1 + "cos 0" = 1 + 1 = 2 At 𝒙=𝟎 𝑓(π‘₯)=π‘˜ 𝒇(𝟎)=π’Œ Since f(x) is continuous at x = 0. L.H.L = R.H.L = 𝑓(0) 𝑓(0)=2 π’Œ=𝟐 So, the correct answer is (B)

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo