Ex 2.4, 8 (iii) - Chapter 2 Class 9 Polynomials
Last updated at Dec. 16, 2024 by Teachoo
Ex 2.4
Ex 2.4, 1 (i)
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Chapter 2 Class 9 Polynomials
Serial order wise
- Ex 2.1
- Ex 2.2
- Ex 2.3
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Ex 2.4
- Examples
- Remainder Theorem
Transcript
Ex 2.4, 8 Factorise each of the following: (iii) 27 – 125a3 – 135a + 225a2 27 – 125a3 – 135a + 225a2 = (3)3 – (5a)3 – 135a + 225a2 = (3)3 – (5a)3 – 45a(3 – 5a) = (3)3 – (5a)3 – 3(3)(5a)(3 – 5a) Using (x – y)3 = x3 – y3 – 3xy (x – y) Putting x = 3, y = 5a = (3 – 5a)3 = (3 – 5a) (3 – 5a) (3 – 5a)
