1. Chapter 2 Class 9 Polynomials (Term 2)
  2. Serial order wise
  3. Ex 2.5

Ex 2.5, 4 (v) - Chapter 2 Class 9 Polynomials (Term 2)

Last updated at Aug. 25, 2021 by

Ex 2.5,4 - Chapter 2 Class 9 Polynomials - Part 5

  1. Chapter 2 Class 9 Polynomials (Term 2)
  2. Serial order wise

    3. Ex 2.5

    Examples →

Transcript

Ex 2.5, 4 Expand each of the following, using suitable identities: (v) (-2x + 5y 3z)2 (-2x + 5y 3z)2 = ( (-2x) + 5y + (-3z) )2 Using (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ac Where a = -2x , b = 5y, c = -3z = (-2x)2 + (5y)2 + (-3z)2 + 2(-2x) (5y) + 2 (5y) (-3z) + 2 (-3z) (-2x) = 4x2 + 25y2 + 9z2 20xy 30yz + 12xz

Chapter 2 Class 9 Polynomials (Term 2)
Serial order wise

About the Author

Davneet Singh's photo - Teacher, Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.