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Ex 2.5,8 - Chapter 2 Class 9 Polynomials - Part 4

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Ex 2.5, 8 Factorise each of the following: (iv) 64a3 – 27b3 - 144a2b + 108ab2 64a3 – 27b3 - 144a2b + 108ab2 = (4a)3 – (3b)3 – 144a2b + 108ab2 = (4a)3 – (3b)3 – 36ab(4a – 3b) = (4a)3 – (3b)3 – 3(4a)(3b)(4a – 3b) Using (x – y)3 = x3 – y3 – 3xy(x – y) Putting x = 4a, y = 3b = (4a – 3b)3 = (4a – 3b) (4a – 3b) (4a – 3b)

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