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Last updated at Aug. 25, 2021 by Teachoo

Transcript

Ex 2.5, 8 Factorise each of the following: (iv) 64a3 – 27b3 - 144a2b + 108ab2 64a3 – 27b3 - 144a2b + 108ab2 = (4a)3 – (3b)3 – 144a2b + 108ab2 = (4a)3 – (3b)3 – 36ab(4a – 3b) = (4a)3 – (3b)3 – 3(4a)(3b)(4a – 3b) Using (x – y)3 = x3 – y3 – 3xy(x – y) Putting x = 4a, y = 3b = (4a – 3b)3 = (4a – 3b) (4a – 3b) (4a – 3b)

Ex 2.5

Ex 2.5, 1 (i)

Ex 2.5, 1 (ii)

Ex 2.5, 1 (iii) Important

Ex 2.5, 1 (iv)

Ex 2.5, 1 (v)

Ex 2.5, 2 (i)

Ex 2.5, 2 (ii) Important

Ex 2.5, 2 (iii)

Ex 2.5, 3 (i)

Ex 2.5, 3 (ii) Important

Ex 2.5, 3 (iii)

Ex 2.5, 4 (i)

Ex 2.5, 4 (ii)

Ex 2.5, 4 (iii) Important

Ex 2.5, 4 (iv)

Ex 2.5, 4 (v)

Ex 2.5, 4 (vi)

Ex 2.5, 5 (i)

Ex 2.5, 5 (ii) Important

Ex 2.5, 6 (i)

Ex 2.5, 6 (ii)

Ex 2.5, 6 (iii)

Ex 2.5, 6 (iv) Important

Ex 2.5, 7 (i)

Ex 2.5, 7 (ii)

Ex 2.5, 7 (iii) Important

Ex 2.5, 8 (i)

Ex 2.5, 8 (ii)

Ex 2.5, 8 (iii) Important

Ex 2.5, 8 (iv) Important You are here

Ex 2.5, 8 (v)

Ex 2.5, 9 (i)

Ex 2.5, 9 (ii)

Ex 2.5, 10 (i) Important

Ex 2.5, 10 (ii)

Ex 2.5, 11

Ex 2.5,12 Important Deleted for CBSE Board 2022 Exams

Ex 2.5,13 Deleted for CBSE Board 2022 Exams

Ex 2.5, 14 (i) Deleted for CBSE Board 2022 Exams

Ex 2.5, 14 (ii) Important Deleted for CBSE Board 2022 Exams

Ex 2.5, 15 (i)

Ex 2.5, 15 (ii) Important

Ex 2.5, 16 (i)

Ex 2.5, 16 (ii) Important

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.