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Ex 2.5, 4 (iii) - Chapter 2 Class 9 Polynomials (Term 2)
Last updated at Aug. 25, 2021 by Teachoo
Ex 2.5
Ex 2.5, 1 (i)
Ex 2.5, 1 (ii)
Ex 2.5, 1 (iii) Important
Ex 2.5, 1 (iv)
Ex 2.5, 1 (v)
Ex 2.5, 2 (i)
Ex 2.5, 2 (ii) Important
Ex 2.5, 2 (iii)
Ex 2.5, 3 (i)
Ex 2.5, 3 (ii) Important
Ex 2.5, 3 (iii)
Ex 2.5, 4 (i)
Ex 2.5, 4 (ii)
Ex 2.5, 4 (iii) Important You are here
Ex 2.5, 4 (iv)
Ex 2.5, 4 (v)
Ex 2.5, 4 (vi)
Ex 2.5, 5 (i)
Ex 2.5, 5 (ii) Important
Ex 2.5, 6 (i)
Ex 2.5, 6 (ii)
Ex 2.5, 6 (iii)
Ex 2.5, 6 (iv) Important
Ex 2.5, 7 (i)
Ex 2.5, 7 (ii)
Ex 2.5, 7 (iii) Important
Ex 2.5, 8 (i)
Ex 2.5, 8 (ii)
Ex 2.5, 8 (iii) Important
Ex 2.5, 8 (iv) Important
Ex 2.5, 8 (v)
Ex 2.5, 9 (i)
Ex 2.5, 9 (ii)
Ex 2.5, 10 (i) Important
Ex 2.5, 10 (ii)
Ex 2.5, 11
Ex 2.5,12 Important
Ex 2.5,13
Ex 2.5, 14 (i)
Ex 2.5, 14 (ii) Important
Ex 2.5, 15 (i)
Ex 2.5, 15 (ii) Important
Ex 2.5, 16 (i)
Ex 2.5, 16 (ii) Important
Transcript
Ex 2.5, 4 Expand each of the following, using suitable identities: (iii) (-2x + 3y + 2z)2 ( 2x + 3y + 2z)2 = (( 2x) + 3y + 2z)2 Using (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ac Where a = -2x , b = 3y, c = 2z = (-2x)2 + (3y)2 + (2z)2 + 2(-2x) (3y) + 2 (3y) (2z) + 2 (2z) (-2x) = 4x2 + 9y2 + 4z2 12xy + 12yz 8xz
