1. Chapter 2 Class 9 Polynomials (Term 2)
  2. Serial order wise
  3. Ex 2.5

Ex 2.5, 4 (iii) - Chapter 2 Class 9 Polynomials (Term 2)

Last updated at Aug. 25, 2021 by

Ex 2.5,4 - Chapter 2 Class 9 Polynomials - Part 3

  1. Chapter 2 Class 9 Polynomials (Term 2)
  2. Serial order wise

    3. Ex 2.5

    Examples →

Transcript

Ex 2.5, 4 Expand each of the following, using suitable identities: (iii) (-2x + 3y + 2z)2 ( 2x + 3y + 2z)2 = (( 2x) + 3y + 2z)2 Using (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ac Where a = -2x , b = 3y, c = 2z = (-2x)2 + (3y)2 + (2z)2 + 2(-2x) (3y) + 2 (3y) (2z) + 2 (2z) (-2x) = 4x2 + 9y2 + 4z2 12xy + 12yz 8xz

Chapter 2 Class 9 Polynomials (Term 2)
Serial order wise

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.