### Advertisement

Last updated at Aug. 25, 2021 by Teachoo

Transcript

Ex 2.5, 3 Factorise the following using appropriate identities: (ii) 4y2 4y + 1 4y2 4y + 1 = 22 y2 4y + 12 = (2y)2 4y + 12 = (2y)2 2 (2y) (1) + (1)2 Using Identity (a b)2 = a2 + b2 2ab Where a = 2y , b = 1 = (2y 1)2 = (2y 1) (2y 1)

Ex 2.5

Ex 2.5, 1 (i)

Ex 2.5, 1 (ii)

Ex 2.5, 1 (iii) Important

Ex 2.5, 1 (iv)

Ex 2.5, 1 (v)

Ex 2.5, 2 (i)

Ex 2.5, 2 (ii) Important

Ex 2.5, 2 (iii)

Ex 2.5, 3 (i)

Ex 2.5, 3 (ii) Important You are here

Ex 2.5, 3 (iii)

Ex 2.5, 4 (i)

Ex 2.5, 4 (ii)

Ex 2.5, 4 (iii) Important

Ex 2.5, 4 (iv)

Ex 2.5, 4 (v)

Ex 2.5, 4 (vi)

Ex 2.5, 5 (i)

Ex 2.5, 5 (ii) Important

Ex 2.5, 6 (i)

Ex 2.5, 6 (ii)

Ex 2.5, 6 (iii)

Ex 2.5, 6 (iv) Important

Ex 2.5, 7 (i)

Ex 2.5, 7 (ii)

Ex 2.5, 7 (iii) Important

Ex 2.5, 8 (i)

Ex 2.5, 8 (ii)

Ex 2.5, 8 (iii) Important

Ex 2.5, 8 (iv) Important

Ex 2.5, 8 (v)

Ex 2.5, 9 (i)

Ex 2.5, 9 (ii)

Ex 2.5, 10 (i) Important

Ex 2.5, 10 (ii)

Ex 2.5, 11

Ex 2.5,12 Important Deleted for CBSE Board 2022 Exams

Ex 2.5,13 Deleted for CBSE Board 2022 Exams

Ex 2.5, 14 (i) Deleted for CBSE Board 2022 Exams

Ex 2.5, 14 (ii) Important Deleted for CBSE Board 2022 Exams

Ex 2.5, 15 (i)

Ex 2.5, 15 (ii) Important

Ex 2.5, 16 (i)

Ex 2.5, 16 (ii) Important

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.