Ex 2.4, 3 (ii) - Chapter 2 Class 9 Polynomials

Last updated at Dec. 16, 2024 by

Ex 2.4, 3 (ii) - Factorise 4y^2 - 4y + 1 using appropriate identities - Ex 2.4

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Ex 2.4, 3 Factorise the following using appropriate identities: (ii) 4y2 4y + 1 4y2 4y + 1 = 22 y2 4y + 12 = (2y)2 4y + 12 = (2y)2 2 (2y) (1) + (1)2 Using Identity (a b)2 = a2 + b2 2ab Where a = 2y , b = 1 = (2y 1)2 = (2y 1) (2y 1)

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