1. Chapter 2 Class 9 Polynomials (Term 2)
  2. Serial order wise
  3. Ex 2.5

Ex 2.5, 1 (iv) - Chapter 2 Class 9 Polynomials (Term 2)

Last updated at Aug. 25, 2021 by

Ex 2.5, 1 - Chapter 2 Class 9 Polynomials - Part 4

  1. Chapter 2 Class 9 Polynomials (Term 2)
  2. Serial order wise

    3. Ex 2.5

    Examples →

Transcript

Ex 2.5, 1 Use suitable identities to find the following products: (iv) (y2 + 3/2 ) (y2 – 3/2 ) (y2 + 3/2 ) (y2 – 3/2) By using the identity (a + b) (a – b) = a2 – b2 , where a = y2 , b = 3/2 = (y2)2 – (3/2)^2 = y4 – 9/4

Chapter 2 Class 9 Polynomials (Term 2)
Serial order wise

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.