Ex 2.4
Ex 2.4, 1 (ii)
Ex 2.4, 1 (iii) Important
Ex 2.4, 1 (iv)
Ex 2.4, 1 (v)
Ex 2.4, 2 (i) Deleted for CBSE Board 2025 Exams
Ex 2.4, 2 (ii) Important
Ex 2.4, 2 (iii)
Ex 2.4, 3 (i) Deleted for CBSE Board 2025 Exams
Ex 2.4, 3 (ii) Important
Ex 2.4, 3 (iii)
Ex 2.4, 4 (i) Deleted for CBSE Board 2025 Exams
Ex 2.4, 4 (ii)
Ex 2.4, 4 (iii) Important
Ex 2.4, 4 (iv)
Ex 2.4, 4 (v)
Ex 2.4, 4 (vi)
Ex 2.4, 5 (i) Deleted for CBSE Board 2025 Exams
Ex 2.4, 5 (ii) Important
Ex 2.4, 6 (i)
Ex 2.4, 6 (ii)
Ex 2.4, 6 (iii)
Ex 2.4, 6 (iv) Important
Ex 2.4, 7 (i) Deleted for CBSE Board 2025 Exams
Ex 2.4, 7 (ii)
Ex 2.4, 7 (iii) Important
Ex 2.4, 8 (i)
Ex 2.4, 8 (ii)
Ex 2.4, 8 (iii) Important
Ex 2.4, 8 (iv) Important
Ex 2.4, 8 (v)
Ex 2.4, 9 (i)
Ex 2.4, 9 (ii)
Ex 2.4, 10 (i) Important Deleted for CBSE Board 2025 Exams
Ex 2.4, 10 (ii)
Ex 2.4, 11 Deleted for CBSE Board 2025 Exams
Ex 2.4,12 Important
Ex 2.4,13
Ex 2.4, 14 (i)
Ex 2.4, 14 (ii) Important
Ex 2.4, 15 (i) You are here
Ex 2.4, 15 (ii) Important
Ex 2.4, 16 (i) Deleted for CBSE Board 2025 Exams
Ex 2.4, 16 (ii) Important
Ex 2.4
Last updated at April 16, 2024 by Teachoo
Ex 2.4, 15 Give possible expressions for the length and breadth of each of the following rectangles, in which their areas are given: (i) Area : 25a2 – 35a + 12 First we factorize 25a2 – 35a + 12 We factorize using the splitting the middle term method = 25a2 – 15a – 20a + 12 = 5a(5a – 3) – 4(5a – 3) = (5a – 3) (5a – 4) Hence, Area = (5a – 3) (5a – 4) Area = Length × Breadth Hence, there are two possibilities