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Ex 2.5
Ex 2.5, 1 (ii)
Ex 2.5, 1 (iii) Important
Ex 2.5, 1 (iv)
Ex 2.5, 1 (v)
Ex 2.5, 2 (i) Deleted for CBSE Board 2023 Exams
Ex 2.5, 2 (ii) Important
Ex 2.5, 2 (iii)
Ex 2.5, 3 (i) Deleted for CBSE Board 2023 Exams
Ex 2.5, 3 (ii) Important
Ex 2.5, 3 (iii)
Ex 2.5, 4 (i) Deleted for CBSE Board 2023 Exams
Ex 2.5, 4 (ii)
Ex 2.5, 4 (iii) Important
Ex 2.5, 4 (iv)
Ex 2.5, 4 (v)
Ex 2.5, 4 (vi)
Ex 2.5, 5 (i) Deleted for CBSE Board 2023 Exams
Ex 2.5, 5 (ii) Important
Ex 2.5, 6 (i)
Ex 2.5, 6 (ii)
Ex 2.5, 6 (iii)
Ex 2.5, 6 (iv) Important You are here
Ex 2.5, 7 (i) Deleted for CBSE Board 2023 Exams
Ex 2.5, 7 (ii)
Ex 2.5, 7 (iii) Important
Ex 2.5, 8 (i)
Ex 2.5, 8 (ii)
Ex 2.5, 8 (iii) Important
Ex 2.5, 8 (iv) Important
Ex 2.5, 8 (v)
Ex 2.5, 9 (i)
Ex 2.5, 9 (ii)
Ex 2.5, 10 (i) Important Deleted for CBSE Board 2023 Exams
Ex 2.5, 10 (ii)
Ex 2.5, 11 Deleted for CBSE Board 2023 Exams
Ex 2.5,12 Important
Ex 2.5,13
Ex 2.5, 14 (i)
Ex 2.5, 14 (ii) Important
Ex 2.5, 15 (i)
Ex 2.5, 15 (ii) Important
Ex 2.5, 16 (i) Deleted for CBSE Board 2023 Exams
Ex 2.5, 16 (ii) Important
Last updated at March 22, 2023 by Teachoo
Ex 2.5, 6 Write the following cubes in expanded form: (iv) (x 2/3 y)^3 (x 2/3 y)^3 Using (a b)3 = a3 - b3 3ab(a - b) Where a = x & b = 2/3y = x3 (2/3 y)3 3(x) (2/3 y) (x 2/3 y) = x3 8/27 y3 2xy (x 2/3 y) = x3 8/27 y3 2xy (x) 2xy( 2/3 y) = x3 8/27 y3 2x2y + 4/3 xy2