1. Chapter 2 Class 9 Polynomials (Term 2)
  2. Serial order wise
  3. Ex 2.5

Ex 2.5,13 - Chapter 2 Class 9 Polynomials (Term 2)

Last updated at Nov. 17, 2020 by

Ex 2.5, 13 - If x + y + z = 0, show that x3 + y3 + z3 = 3xyz - Ex 2.5

  1. Chapter 2 Class 9 Polynomials (Term 2)
  2. Serial order wise

    3. Ex 2.5

    Examples →

Transcript

Ex 2.5, 13 If x + y + z = 0, show that x3 + y3 + z3 = 3xyz . We know that x3 + y3 + z3 3xyz = (x + y + z) (x2 + y2 + z2 xy yz zx) Putting x + y + z = 0, x3 + y3 + z3 3xyz = (0) (x2 + y2 + z2 xy yz zx) x3 + y3 + z3 3xyz = 0 x3 + y3 + z3 = 3xyz Hence proved

Chapter 2 Class 9 Polynomials (Term 2)
Serial order wise

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