Get live Maths 1-on-1 Classs - Class 6 to 12
Ex 2.5
Ex 2.5, 1 (ii) You are here
Ex 2.5, 1 (iii) Important
Ex 2.5, 1 (iv)
Ex 2.5, 1 (v)
Ex 2.5, 2 (i) Deleted for CBSE Board 2023 Exams
Ex 2.5, 2 (ii) Important
Ex 2.5, 2 (iii)
Ex 2.5, 3 (i) Deleted for CBSE Board 2023 Exams
Ex 2.5, 3 (ii) Important
Ex 2.5, 3 (iii)
Ex 2.5, 4 (i) Deleted for CBSE Board 2023 Exams
Ex 2.5, 4 (ii)
Ex 2.5, 4 (iii) Important
Ex 2.5, 4 (iv)
Ex 2.5, 4 (v)
Ex 2.5, 4 (vi)
Ex 2.5, 5 (i) Deleted for CBSE Board 2023 Exams
Ex 2.5, 5 (ii) Important
Ex 2.5, 6 (i)
Ex 2.5, 6 (ii)
Ex 2.5, 6 (iii)
Ex 2.5, 6 (iv) Important
Ex 2.5, 7 (i) Deleted for CBSE Board 2023 Exams
Ex 2.5, 7 (ii)
Ex 2.5, 7 (iii) Important
Ex 2.5, 8 (i)
Ex 2.5, 8 (ii)
Ex 2.5, 8 (iii) Important
Ex 2.5, 8 (iv) Important
Ex 2.5, 8 (v)
Ex 2.5, 9 (i)
Ex 2.5, 9 (ii)
Ex 2.5, 10 (i) Important Deleted for CBSE Board 2023 Exams
Ex 2.5, 10 (ii)
Ex 2.5, 11 Deleted for CBSE Board 2023 Exams
Ex 2.5,12 Important
Ex 2.5,13
Ex 2.5, 14 (i)
Ex 2.5, 14 (ii) Important
Ex 2.5, 15 (i)
Ex 2.5, 15 (ii) Important
Ex 2.5, 16 (i) Deleted for CBSE Board 2023 Exams
Ex 2.5, 16 (ii) Important
Last updated at March 28, 2023 by Teachoo
Ex 2.5, 1 Use suitable identities to find the following products: (ii) (x + 8) (x – 10) (x + 8) (x – 10) Using (x + a) (x + b) = x2 + (a + b) x +ab, putting a = 8 , b = -10 = x2 + (8 – 10) x + (8) (-10) = x2 – 2x – 80