1. Chapter 2 Class 9 Polynomials (Term 2)
  2. Serial order wise
  3. Ex 2.5

Ex 2.5, 9 (i) - Chapter 2 Class 9 Polynomials (Term 2)

Last updated at Aug. 25, 2021 by

Ex 2.5, 9 - Verify (i) x3 + y3 = (x + y) (x2 - xy + y2) - Identity VIII

 

  1. Chapter 2 Class 9 Polynomials (Term 2)
  2. Serial order wise

    3. Ex 2.5

    Examples →

Transcript

Ex 2.5, 9 Verify: (i) x3 + y3 = (x + y) (x2 – xy + y2) L.H.S x3 + y3 We know (x + y)3 = x3 + y3 + 3xy (x + y) So, x3 + y3 = (x + y)3 – 3xy (x + y) = (x + y)3 – 3xy (x + y) = (x + y) [ (x + y)2 – 3xy)] Using (a+b)2 = a2 + b2 + 2ab = (x + y) [(x2 + y2 + 2xy) – 3xy] = (x + y) (x2 + y2 – xy) = (x + y) (x2 - xy + y2) = R.H.S R.H.S (x + y) (x2 – xy + y2) Hence proved

Chapter 2 Class 9 Polynomials (Term 2)
Serial order wise

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