1. Chapter 2 Class 9 Polynomials (Term 2)
  2. Serial order wise
  3. Ex 2.5

Ex 2.5, 8 (ii) - Chapter 2 Class 9 Polynomials (Term 2)

Last updated at Aug. 25, 2021 by

Ex 2.5,8 - Chapter 2 Class 9 Polynomials - Part 2

  1. Chapter 2 Class 9 Polynomials (Term 2)
  2. Serial order wise

    3. Ex 2.5

    Examples →

Transcript

Ex 2.5, 8 Factorise each of the following: (ii) 8a3 – b3 – 12a2b + 6ab2 8a3 – b3 – 12a2b + 6ab2 = (2a)3 – (b)3 – 12a2b + 6ab2 = (2a)3 + (b)3 – 6ab (2a – b) = (2a)3 – (b)3 – 3(2a)(b) (2a – b) Using (x – y)3 = x3 – y3 – 3xy(x – y) Putting x = 2a, y = b = (2a – b)3 = (2a – b) (2a – b) (2a – b)

Chapter 2 Class 9 Polynomials (Term 2)
Serial order wise

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.