Example 14 - Chapter 3 Class 11 Trigonometric Functions
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Example 14 Show that tan 3π₯ tan 2π₯ tan π₯ = tan 3π₯ β tan 2π₯ β tan π₯ We know that ππ = ππ+ π Therefore, tan ππ = πππβ‘(ππ + π) tanβ‘3π₯ = tanβ‘γ2π₯ +γ tanγβ‘π₯ γ/(1βtanβ‘γ2π₯ tanβ‘π₯ γ ) " " tanβ‘3π₯βtanβ‘3π₯ tanβ‘2π₯ tanβ‘π₯=tanβ‘2π₯+tanβ‘π₯ tanβ‘3π₯βtanβ‘2π₯βtanβ‘π₯=tanβ‘3π₯ tanβ‘2π₯ tanβ‘π₯ πππβ‘ππ πππβ‘ππ πππβ‘π = πππβ‘ππ β πππβ‘ππ β πππβ‘π
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo