Example 15 - Divide 44(x^4 - 5x^3 - 24x^2) by 11x (x - 8) - Chapter 14

Example 15 - Chapter 14 Class 8 Factorisation - Part 2

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Example 15 Divide 44 (š‘„^4 – 5š‘„^3 – 24š‘„^2) by 11x (x – 8) We first factorize 44 (š‘„^4 – 5š‘„^3 – 24š‘„^2) = 44 (š‘„^2 Ɨ š‘„^2 āˆ’ 5š‘„ Ɨ š‘„^2 āˆ’ 24 Ɨ š‘„^2) Taking š‘„^2 common, = 怖44š‘„ć€—^2 (š‘„^2 āˆ’ 5š‘„ āˆ’ 24) By middle term splitting, = 44š‘„^2 (š‘„^2+3š‘„ āˆ’ 8š‘„ āˆ’ 24) = 44š‘„^2 [(š‘„^2+3š‘„) āˆ’ (8š‘„+24)] Both have x as common factor Both have 8 as common factor Splitting the middle term We need to find two numbers whose Sum = āˆ’5 Product = āˆ’24 So, we write āˆ’5x = 3x āˆ’ 8x = 44š‘„^2 [š‘„(š‘„+3) āˆ’8(š‘„+3)] Taking š‘„+3 common, = 44š‘„^2 (š‘„+3) (š‘„ āˆ’ 8) Dividing (44 (š‘„^4 āˆ’ 5š‘„^3 āˆ’ 24š‘„^2 ))/(11š‘„ (š‘„ āˆ’ 8)) = (44 š‘„^2 (š‘„ + 3) (š‘„ āˆ’ 8))/(11š‘„ (š‘„ āˆ’ 8)) = 44/11 Ɨ š‘„^2/š‘„ Ɨ (š‘„ + 3) Ɨ ((š‘„ āˆ’ 8))/((š‘„ āˆ’ 8)) = 4 Ɨ š‘„ Ɨ (š‘„ + 3) = 4š’™ (š’™ + 3)

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