Ex 12.3, 5 (i) - Factorise and divide (y^2 + 7y + 10) ÷ (y + 5) - Ex 12.3

part 2 - Ex 12.3, 5 (i) - Ex 12.3 - Serial order wise - Chapter 12 Class 8 Factorisation

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Transcript

Ex 12.3, 5 Factorise the expressions and divide them as directed. (i) (๐‘ฆ^2 + 7y + 10) รท (y + 5)We first factorise ๐‘ฆ^2+7๐‘ฆ+10 By middle term splitting, ๐’š^๐Ÿ + 7y +10 = ๐‘ฆ^2 + 2y + 5y + 10 = (๐‘ฆ^2+2๐‘ฆ) + (5๐‘ฆ+10) = y (y + 2) + 5 (y + 2) Taking (y + 2) common, = (y + 2) (y + 5) Splitting the middle term We need to find two numbers whose Sum = 7 Product = 10 So, we write 7y = 2y + 5y Now, Dividing (๐‘ฆ^2+7๐‘ฆ+10)รท(๐‘ฆ+5) = (๐‘ฆ^2 + 7๐‘ฆ + 10)/((๐‘ฆ + 5)) = ((๐’š + ๐Ÿ) (๐’š + ๐Ÿ“))/((๐’š + ๐Ÿ“)) = (๐‘ฆ + 2) ร— ((๐‘ฆ + 5))/((๐‘ฆ + 5)) = (๐’š + 2)

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