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Ex 14.3, 5 (i) - Chapter 14 Class 8 Factorisation
Last updated at Dec. 26, 2018 by Teachoo
Dividing two polynomials
Dividing polynomial by polynomial
Ex 14.3, 4 (i)
Ex 14.3, 4 (v) Important
Ex 14.3, 4 (iv)
Ex 14.3, 4 (ii) Important
Ex 14.3, 4 (iii)
Ex 14.3, 3 (i)
Ex 14.3, 3 (ii)
Ex 14.3, 3 (iii) Important
Ex 14.3, 3 (iv)
Ex 14.3, 3 (v) Important
Ex 14.3, 5 (i) You are here
Ex 14.3, 5 (ii) Important
Ex 14.3, 5 (iii)
Ex 14.3, 5 (iv) Important
Ex 14.3, 5 (v)
Ex 14.3, 5 (vi)
Ex 14.3, 5 (vii) Important
Example 15 Important
Example 16
Transcript
Ex 14.3, 5 Factorise the expressions and divide them as directed. (i) (π¦^2 + 7y + 10) Γ· (y + 5) We first factorise π¦^2+7π¦+10 By middle term splitting, π¦^2 + 7y +10 = π¦^2 + 2y + 5y + 10 = (π¦^2+2π¦) + (5π¦+10) = y (y + 2) + 5 (y + 2) Taking (y + 2) common, = (y + 2) (y + 5) Splitting the middle term We need to find two numbers whose Sum = 7 Product = 10 So, we write 7y = 2y + 5y Now, Dividing (π¦^2+7π¦+10)Γ·(π¦+5) = (π¦^2 + 7π¦ + 10)/((π¦ + 5)) = ((π¦ + 2) (π¦ + 5))/((π¦ + 5)) = (π¦ + 2) Γ ((π¦ + 5))/((π¦ + 5)) = (π + 2)
