(2𝑥y + 2y) + (3𝑥 + 3)
Both have 2 & y
as common factor
Both have 2 & y
as common factor
= 2y (𝑥 + 1) + 3 (𝑥 + 1)
Now, (𝑥 + 1) is common between them both
= (𝑥 + 1) (2y + 3)
So,
2𝑥y + 3𝑥 + 2y + 3 = (𝑥 + 1) (2y + 3)
Factorise 4ab − 5a + 12b + 15
4ab − 5a + 12b + 15
= (4ab − 12b) + (15 − 5a)
Both have 4 & b
as common factor
Both have 3
as common factor
= 4b (a − 3) + 5 (3 − a)
Writing (3 − a) = −(a − 3)
= 4b (a − 3) − 5 (a − 3)
Taking (a − 3) common
= (a − 3) (4b − 5)

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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