(2๐ฅy + 2y) + (3๐ฅ + 3)
Both have 2 & y
as common factor
Both have 2 & y
as common factor
= 2y (๐ฅ + 1) + 3 (๐ฅ + 1)
Now, (๐ฅ + 1) is common between them both
= (๐ฅ + 1) (2y + 3)
So,
2๐ฅy + 3๐ฅ + 2y + 3 = (๐ฅ + 1) (2y + 3)
Factorise 4ab โ 5a + 12b + 15
4ab โ 5a + 12b + 15
= (4ab โ 12b) + (15 โ 5a)
Both have 4 & b
as common factor
Both have 3
as common factor
= 4b (a โ 3) + 5 (3 โ a)
Writing (3 โ a) = โ(a โ 3)
= 4b (a โ 3) โ 5 (a โ 3)
Taking (a โ 3) common
= (a โ 3) (4b โ 5)

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.