Suppose we want to factorise,

**
Β 2
**
**
x
**
**
y + 3
**
**
x
**
**
+ 2y + 3
**

Β

We note that,

Β Β 2xy & 2y both have 2

And

Β 3x & 3 both have 3

Β

So, we put them together

Β

Β (2xy + 2y) + (3π₯ + 3)

Β

So,

Β 2π₯y + 3π₯ + 2y + 3 = (π₯ + 1) (2y + 3)

### Β

### Factorise 4ab β 5a β 12b + 15